She would lose <span> 2,880 Joules (J) of energy </span>
To find the work done on the particle, the following is the
solution:
Dw = F dx
W = integral over the path ( F(x) dx)
W = integral from 0 to 1 (e^(-x/5 + 5) dx)
W = -5e^(-x/5 + 5) from 0 to 1
W = 135 J
The work done is 135 J.
Force on a moving charge is given by formula

here we know that this force will be maximum when velocity is perpendicular to magnetic field

here we know that



now we have

