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Pie
3 years ago
10

Which type of bond makes it possible for a macromolecule to interact with great specificity with just one out of the many thousa

nds of different molecules present inside a cell?
Chemistry
1 answer:
Andrei [34K]3 years ago
7 0

Answer:Non-covalent bonds

Explanation:

The Non-covalent bonds are bonds such as van der Waals forces of attraction, the Hydrogen bonds, hydrophobic bonds and so on. The Non-covalent bonds are very important types of bonding in large biological molecules.

Just like the question says, the Non-covalent bonds, ''makes it possible for a macromolecule to interact with great specificity with just one out of the many thousands of different molecules present inside a cell".

Ionic bonding is also a Non-covalent bonding. They(Non-covalent bonds) helps in the stability of large macromolecules.

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3 years ago
The American Heart Association recommends to eat no more than 2,301mg of sodium per day. Convert the mass of
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The mass of 2,301 grams of sodium in ounces is 0.0811757609 ounces.

The amount of sodium recommended by American heart association is 2301 mg. This limit should not be crossed in a day.

We have to convert Mass of sodium from mg to ounces.

We know,

1 ounce = 28.3459 grams.

We also know,

1 gram = 1000 milligrams.

So,

28.3459 grams = 28.3459 x 1000 milligrams.

28.3459 grams = 28345.9 milligrams.

1 ounce = 28345.9 mg.

1 mg = 1/28345.9 ounces

Weight of sodium 2301mg in ounces,

2301mg = 2301/28345.9 ounces

Dividing till last significant figure,

2301 mg = 0.0811757609 ounces.

Mass of sodium in ounces is 0.0811757609.

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1 year ago
On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i
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Answer:

1.6 L

Explanation:

Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 1.5 L

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T₁ = 12 °C

T₂ = 32 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

T₂ = (32 + 273.15) K = 305.15 K  

Using above equation as:

\frac{1.5}{285.15}=\frac{V_2}{305.15}

V_2=\frac{1.5\cdot \:305.15}{285.15}

New volume = 1.6 L

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