Answer is valence electron, they all have total of 2 valence electron.
remember group number = valence electron
Answer: 5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.
Further Explanation:
We can convert from number of representative particles to moles using the formula:

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

Learn More
- Learn more about representative particles brainly.com/question/8969313
- Learn more about Avogadro's number brainly.com/question/229300
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Keywords: moles conversion, Avogadro's number
Answer: E
How much NH₃ can be produced from the reaction below:
N₂ + 3H₂ - 2NH₃
The stoichiometric ratio of the reactants = 1:3
Given
74.2g of N₂, and Molar mass = 14g/mole
Mole of N₂ = 74.2/14=5.3mols of N₂,
and 14mols of H₂
From this given values and comparing with the stoichiometric ratio, H₂ will be the limiting reagent while N₂ is the excess reactant.
i.e, for every 14mols of H₂, we need 4.67mols of N₂ to react with it to produce 9.33mols of NH₃ as shown (vice versa)
From this we have 9.33mols of NH₃ produced
Avogadro constant, we have n = no of particles = 6.022x10²³ molecules contained in every mole of an element.
For a 9.33mols of NH3, we have 9.33x6.022x10²³molecules in NH3
5.62x10²⁴molecules of NH₃
Answer:
1.05 × 10⁻⁸ N
Explanation:
Using Coulomb's law
F force of attraction between them = k
= k 
K coulomb constant = 8.99 × 10⁹ N m²C⁻²
Z₁ = + 2 ( valency electron)
Z₂ = -1 ( valency electron)
r is the distance between then since they just touch one another = 0.085 nm + 0.125 nm = 0.21 nm = 0.21 × 10⁻⁹ m
q charge = 1.602 × 10⁻¹⁹ C of an electron
F = ( 2 × 1 × 8.99 × 10⁹ N m²C⁻² × (1.602 × 10⁻¹⁹ C)² / ( 0.21 × 10⁻⁹ m )² = 1046.34 × 10 ⁻¹¹ = 1.05 × 10⁻⁸ N