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jek_recluse [69]
4 years ago
8

How does increased temperature affect the amount of salt, carbon, and other substances able to dissolve in the ocean? What are t

he resulting effects?
Chemistry
1 answer:
astra-53 [7]4 years ago
5 0

Answer:

For solid salts that are soluble in the sea water, as the sea water temperature rises, the solubility of the salt in the water increases. The accompanying increase in the kinetic energy of solvent water molecules with the increase in the temperature of the seawater results in the increase in the number of solute salt inter-molecular bonds being broken by the energetic solvent molecules resulting in increasing solubility of the solids

However, for gases, the increase in temperature of the sea water results in a decrease in the solubility of all gases. The process is also explainable by the kinetic theory such that a rise in temperature of the gas seawater solution increases the kinetic energy of both the solvent water and the solute gas. The higher energy gases are moving much faster and are then  then able to separate from the less mobile liquid gas combination.

The resulting effects

1) The surface (topmost) hotter portions of the sea have fewer living organisms

2) Fishes that come to the surface frequently gas for air by bringing their head above water

3) Most of the life forms are located deep within the sea

4) Formation of water movement cycles within the ocean and polar water bodies

5) Mechanical nature of the sea compared to fresh water bodies

Explanation:

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4 years ago
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Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a
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solution:

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3 years ago
1/2-life of pyruvic acid in the presence of aminotransferase enzyme (which converts it to alanine) was found to be 221 s. how lo
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Answer:

After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.

Explanation:

The first order kinetics reaction is:

ln [A] = ln [A]₀ - kt

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To convert half-life to k you must use:

t(1/2) = ln 2 / K

221s = ln 2 / K

K = ln 2 / 221s

<h3>K = 3.1364x10⁻³s⁻¹</h3>

If [A] = 1/64, [A]₀ = 1:

ln [A] = ln [A]₀ - kt

ln (1/64) = ln 1 - 3.1364x10⁻³t

4.1588 = 3.1364x10⁻³s⁻¹t

1326s = t

<h3>After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.</h3>

<em />

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