Answer:
The friction force and the x component for the weight should be the reaction forces that are opposite and equal to the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.
Explanation:
<u>When the locomotive starts to pull the train up, appears two reaction forces opposed to the action force in the direction of the move. </u>
The first one is due to the friction between the wheels and the ground, it will be the friction force (Fr):
Fr = μ*Pₓ =μmg*sin(φ)
<em>where μ: friction dynamic coefficient, Pₓ: is the weight component in the x-axis, m: total mass = train's mass + locomotive's mass, g: gravity, and sin(φ): is the angle respect to the x-axis.</em>
And the second one is the x component for the weight (Wₓ):
Wₓ = mg*cos(φ)
<em>where cos(φ): is the angle respect to the y-axis. </em>
<em> </em>
These two forces should be the same as the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.
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You'll get destructive interference if both waves are the same frequency but the peaks of one wave overlap the troughs of the other wave.
That can only happen if one wave has to travel (1/2 wavelength) farther than the other one to reach your ears. So we want to find the lowest frequency for which 52 cm is 1/2 of a wavelength ... the wavelength is 104 cm.
Frequency = (speed) / (wavelength)
Frequency = (344 m/s) / (104 cm)
Frequency = (344 m/s) / (1.04 meter)
Frequency = (344 / 1.04) per second
Frequency = 330.8 Hz .
Answer:
The displacement of the boat is 7.41 m
Explanation:
Given;
initial velocity of the motorboat, u = 6.5 m/s west
final velocity of the motorboat, v = 1.5 m/s west
acceleration of the motorboat, a = -2.7 m/s² east
The displacement of the boat is given by;
v² = u² + 2ad
where;
d is the displacement of the motorboat
1.5² = 6.5² + 2(-2.7)d
1.5² - 6.5² = -5.4d
-40 = -5.4d
d = (40) / 5.4
d = 7.41 m
Therefore, the displacement of the boat is 7.41 m
