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3 years ago

6

How does the speed of an object relate to the energy of the object

1 answer:

Ann [662]3 years ago

7 0

Answer:

Increasing the speed of an object decreases its motion energy. Increasing the speed of an object increases its motion energy. Increasing the speed of an object does not affect its motion energy. Whether or not its motion energy is affected depends on how much its speed was increased.

Explanation:

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Jose was out drinking with his friends for nearly the whole night. The next morning he was confused and vomiting, and had a low

Lady bird [3.3K]

Answer:

He has a hangover.

Explanation:

Just something I know.

6 0

2 years ago

A man takes 20 seconds to climb 5m up a ladder. He weighs 720N. Calculate the power he must deliver to do this.

Inessa05 [86]

Answer:

180 W

Explanation:

The work done by the man against gravity is equal to its gain in gravitational potential energy:

$W=mg\Delta h$

where

(mg) = 720 N is the weight of the man

$\Delta h= 5 m$ is the change in height

Substituting,

$W=(720)(5)=3600 J$

The power he must deliver is given by

$P=\frac{W}{t}$

where

W = 3600 J

t = 20 s is the time taken

Substituting,

$P=\frac{3600}{20}=180 W$

3 0

3 years ago

A compass in a magnetic field will line up __________.

Anastaziya [24]

Line up in a direction parallel to the magnetic field lines<span />

5 0

3 years ago

Which statement describes an example of static electricity?

lana [24]

Answer: Negatively charged particles are repelled by other negatively charged particles

Explanation:

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3 years ago

Read 2 more answers

A cube-shaped piece of copper has sides of 4cm each and it's density is

iris [78.8K]

Answer:

$64 cm^3$

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

We have a cube-shaped piece of copper of 4 cm of side length. The volume of the piece is:

$V=(4\ cm)^3=64\ cm^3$

Surprisingly, no other magnitude is required, thus the answer is:

$\mathbf{64 cm^3}$

5 0

2 years ago