Commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
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What are the technologies that could help reduce the damage from a tsunami?</h3>
Commonly seawalls are used for preventing damage from tsunamis. There is a network which is used for detecting the earthquake and tsunami and that network is known as Seismological network. This network helps the people to know about the earthquakes and tsunamis and reduces the damages of earthquakes and tsunamis.
The engineers also design a special type of special buoys which is also known as floating devices, these devices are placed near the coastal areas from where the tsunamis can be detected easily.
So we can conclude that commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
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Answer:
Empirical formula is: C₂H₅
Explanation:
The chemical equation of burning of a compound that conatins only Carbon and Hydrogen is:
CₓHₙ + O₂ → XCO₂ + n/2H₂O
That means the moles of CO₂ produced are the moles of Carbon in the compound and moles of hydrogen are twice moles of water. Empirical formula is the simplest ratio between moles of each element in the compound. Thus, finding molse of C and moles of H we can find empirical formula:
<em>Moles C and H:</em>
Moles C = Moles CO₂:
7.851g CO₂ ₓ (1mol / 44g) = 0.1784 moles CO₂ = Moles C
<em />
Moles H = 2 Moles H₂O
4.018g H₂O ₓ (1mol / 18.01g) = 0.2231 * 2 = 0.4417 moles H
<em>Ratio C:H</em>
The ratio between moles of hydrogen and moles of Carbon are:
0.4417 moles H / 0.1784 moles C = 2.5
That means there are 2.5 moles of H per mole of Carbon. As empirical formula must be given only in whole numbers,
<h3>Empirical formula is: C₂H₅</h3>
Average atomic mass of an element=Atomic mass isotope₁* percent abundance isotope₁ + Atomic mass isotope₂* percent abundance isotope₂+<span>Atomic mass isotope</span>₃<span>* percent abundance isotope</span>₃....
average atomic mass=39.96 u*0.9959+37.96 u*0.00065+
35.97 u*0.00366≈39.95 u
Answer: the average atomic mass of this element is 39.95 u
Answer:
Q = 440 J
Explanation:
Given data:
Heat required = ?
Initial temperature = 25°C
Final temperature = 40°C
Mass in gram = 20 g
Specific heat capacity = 1.1 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40°C - 20°C
ΔT = 20°C
Q = 20 g×1.1 J/g.°C × 20°C
Q = 440 J