Answer:
H = start height (v = 0)
h = present height
v = present speed
assuming no friction
total energy = PE + KE
mgH = mgh + .5mv^2
if PE = KE then
mgH = mgh + mgh
h = H/2
potential energy = kinetic energy when object is at half its start height.
Explanation:
The problem seems to be incomplete because there is no question. However, from the problem description, the logical question is to find he acceleration needed by the jet to land on the airplane carrier. The working equation would be:
2ad = v₂² - v₁²
Since the jet stops, v₂ = 0. Substituting the values:
2(a)(95 m) = 0² - [(240 km/h)(1000 m/1 km)(1h/3600 s)]²
Solving for a,
<em>a = -23.39 m/s² (the negative sign indicates that the jet is decelerating)</em>
Larger stars have a higher amount of fuel in order to keep the process of nuclear fusion going.
7) 6, i believe, (Cu) 1 atom+ (S) 1 atom+(0)4 atoms.
Which of these is an example of convection?
<u>
A. an egg boiling in water
</u>
B. an egg frying in a pan
C. an egg exposed to a flame
D. an egg warming under a light
