First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
<h3>
First harmonic of a closed pipe</h3>
The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.
L = λ/4
where;
- L is the length of the pipe
- λ is the wavelength of sound
λ = 4L
But, v = F₀λ
v = F₀(4L)
F₀ = v/4L
where;
- F₀ is the first harmonic
- v is speed of sound
Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
Learn more about fundamental frequency here: brainly.com/question/1967686
#SPJ11
<h3 />
Answer:i would say "to treat or prevent injuries"
Explanation: anaerobic exercise is: "high intensity movements preformed in a short period of time."
to treat or prevent injuries you would want to do Aerobic exercise, which is an easy exercise like walking.
<span>We need to calculate the resistance of a clock which draws current I=0.5A and is connected to a circuit of V=120V. We can find the resistance of a circuit from Ohm's law: I=U/R where I is the current, U is the voltage and R is the resistance. So lets manipulate Ohm's law to find the resistance: R=U/I. Now we input our numbers: R=120V/0.5A and we get R=240 Ohm. So the resistance is R=240 Ohm.</span>
Answer:
0.614 nm
Explanation:
Energy of the nth state of one dimensional infinite wall is,
Given the energy to excite an electron from ground state to first excited state is,
And the Plank's constant is, 
Mass of electron,
Now the energy will of a 1 dimensional infinite wall which excite an electron from ground state to first excited state will be,
Put all the variables in above equation and rearrange it for L.
Therefore the width of the box is 0.614 nm.
