Ipt Which of the following is true about semipermeable membranes?
1 answer:
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1.5 % is the percent yield in the reaction.
Explanation:
Given that:
original mass of the sample used in reaction = 1.897 grams
product formed after decomposition = 1.071 grams
The reaction for the decomposition:
Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)
It says that 1 mole of Mg(HCO3)2 yielded 1 mole of MgCO2 on decomposition
68.31 grams/mole or 68.31 grams of MgCO2 is formed
percent yield = x 100
putting the values in the equation:
percent yield =
= 0.015 x100
PERCENT YIELD = 1.5 %
Answer:
The mass percentage composition of nitrogen in the sample of the cleaning detergent is approximately 16.78%
Explanation:
The given mass of the sample of the cleaning detergent, m₁ = 20.5 g
The mass of the ammonium hydroxide, NH₄OH in the detergent, m₂ = 8.61 g
The molar mass of NH₄OH = 35.04 g/mol
The molar mass of nitrogen, N = 14.01 g/mol
Therefore, the mass, m₃ of nitrogen, N, in 8.61 g of ammonium hydroxide, NH₄OH, is found as follows;
m₃ = (14.01/35.04) × 8.61 g = (402,087/118,800) g ≈ 3.44 g
The mass of nitrogen, N, in the ammonium hydroxide, NH₄OH, contained in the 20.5 g sample of the cleaning agent, m₃ ≈ 3.44 grams
The percentage composition of nitrogen in the sample of the cleaning detergent, %N is given as follows;
Therefore;
%N ≈ ((3.44 g)/(20.5 g)) × 100 ≈ 16.78 %
The percentage composition of nitrogen, %N ≈ 16.78%.