Here is the answer. I am not sure how to explain it! Sorry!
The specific heat capacity of water is 4200J/(kg*℃). So when absorbs 209 joules, the water sample will increase 209/(4200*0.01)=5℃. So the final temperature of sample is 23+5=28℃.
<u>Answer:</u> The final temperature of the system is 14.60°C
<u>Explanation:</u>
When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

......(1)
where,
q = heat absorbed or released
= mass of aluminium = 25.00 g
= mass of water = 100 g
= final temperature = ?°C
= initial temperature of aluminium = 100°C
= initial temperature of water = 10°C
= specific heat of aluminium = 0.900 J/g°C
= specific heat of water= 4.18 J/g°C
Putting values in equation 1, we get:
![25\times 0.900\times (T_{final}-100)=-[100\times 4.18\times (T_{final}-10)]](https://tex.z-dn.net/?f=25%5Ctimes%200.900%5Ctimes%20%28T_%7Bfinal%7D-100%29%3D-%5B100%5Ctimes%204.18%5Ctimes%20%28T_%7Bfinal%7D-10%29%5D)

Hence, the final temperature of the system is 14.60°C
Answer:
6.18 g
Explanation:
We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
: 41.99
Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O
<em>n</em>/mol: 0.58
1. Use the molar ratio of NaF:HF to calculate the moles of NaF.

2. Use the molar mass of NaF to calculate the mass of NaF.
