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oksian1 [2.3K]
3 years ago
10

Lucia has a bedroom window that gets direct sun in the afternoon and her room gets hot. She puts some mylar (a shiny plastic) on

the outside of her window.
1. How might this change the temperature in her room? Use what you know about light to explain your answer.
Physics
1 answer:
ad-work [718]3 years ago
8 0
The heat form the Mylar outside her window may transfer the heat to the walls. Which then tanker the heat inside Lucia’s home.
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A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 10.0 m/s2. A 20 kg ma
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Answer

given,

mass = 100 kg

acceleration = 10 m/s²

A mass 20 kg slides over 100 kg block

acceleration = 3 m/s²

horizontal friction exerted by the 100 kg block on 20 kg

using newton's second law

F - f = 0

F = f

f = ma

f = 20 × 3

f = 60 N

now net force acting on the 100 kg block

F_net = m a

F_net = 100 x 10

F_net = 1000 N

after 20 kg block falls the acceleration of the bock

F = 1000 +60

F = 1060 N

acceleartion on the block

a = \dfrac{F}{m}

a = \dfrac{1060}{100}

a = 10.60 m/s²

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3 years ago
Question 15 (3.33 points) Solve: What work is done when 3.0 C is moved through an electric potential difference of 1.5 V?
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Answer:

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Explanation:

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3 years ago
Uncle Harry weighs 80 newtons. What is his mass in<br> kilograms?
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Answer:

8.158 Kilograms Force

Explanation:

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2 years ago
Read 2 more answers
alculate the kinetic energies of (a) a 2.00×103-kg automobile moving at 100.0 km/h; (b) an 80.0-kg runner sprinting at 10.0 m/s;
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Answer:

(a) 7.72×10⁵ J

(b) 4000 J

(c) 1.82×10⁻¹⁶ J

Explanation:

Kinetic Energy: This can be defined energy of a body due to its motion. The expression for kinetic energy is given as,

Ek = 1/2mv²................... Equation 1

Where Ek = Kinetic energy, m = mass, v = velocity

(a)

For a moving automobile,

Ek = 1/2mv².

Given: m = 2.0×10³ kg, v = 100 km/h = 100(1000/3600) m/s = 27.78 m/s

Substitute into equation 1

Ek = 1/2(2.0×10³)(27.78²)

Ek = 7.72×10⁵ J

(b)

For a sprinting runner,

Given: m = 80 kg, v = 10 m/s

Substitute into equation 1 above,

Ek = 1/2(80)(10²)

Ek = 40(100)

Ek = 4000 J

(c)

For a moving electron,

Given: m = 9.10×10⁻³¹ kg, v = 2.0×10⁷ m/s

Substitute into equation 1 above,

Ek = 1/2(9.10×10⁻³¹)(2.0×10⁷)²

Ek = 1.82×10⁻¹⁶ J

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3 years ago
What are some common characteristics that infectious agents like viruses bacteria fungi and parasites have in common and what ar
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