4 years ago

Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.

Mathematics

1 answer:

sineoko [7]4 years ago

5 0

Zeros are the x-values that make the function zero.
0 = (x-0)(x- -4)(x-3)

f(x) = x(x+4)(x-3)

You might be interested in

Your question here (keep it simple and clear to get the best answer)

ZanzabumX [31]

What is the largest organ in your body?

7 0

3 years ago

I need help quick please help me thnak you

quester [9]

Answer:

28 numbers

Step-by-step explanation:

There is a distance of 81 between -0.5 and 80.5. Divide this number by 3, since you are only counting every third number and you will get 27, but you need to count the first number, which has been excluded. Add one more to get the answer, 28.

3 0

3 years ago

C=-7/15 and x=2/5 c-4x write your answer in simplest form

pogonyaev

9514 1404 393

Answer:

-31/15

Step-by-step explanation:

Put the numbers in the expression and do the arithmetic.

$c-4x=-\dfrac{7}{15}-4\cdot\dfrac{2}{5}=-\left(\dfrac{7}{15}+\dfrac{8}{5}\right)\\\\=-\left(\dfrac{7}{15}+\dfrac{24}{15}\right)=\boxed{-\dfrac{31}{15}}$