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3 years ago

If a solution had an [OH-] = 3.00 x 10-10 moles/liter, what would be the pH value of this solution? 3.53 4.48

Chemistry

1 answer:

UNO [17]3 years ago

3 0

Answer:

4.48

Explanation:

p[OH-] = - log(3.00 *10^-10) = 9.52

pH + pOH = 14

pH = 14 - 9.52= 4.48

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