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3 years ago

If a solution had an [OH-] = 3.00 x 10-10 moles/liter, what would be the pH value of this solution? 3.53 4.48

Chemistry

1 answer:

UNO [17]3 years ago

3 0

Answer:

4.48

Explanation:

p[OH-] = - log(3.00 *10^-10) = 9.52

pH + pOH = 14

pH = 14 - 9.52= 4.48

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jake pushes a heavy box across a carpeted floor.Name three forces that act on the box, and explain how you know these are unbale

Fantom [35]

I actually learned about this stuff about 3 years ago and this is what I can tell you what I remember and hopefully it helps in a way...
[Newton’s law of motion]
There’s unbalanced forces, friction, and balanced forces.
Unbalanced forces is where the object (in this case the box) is moving in one direction because one of the forces is applying more pressure than the other
Friction is where the box would be harder to push but if it’s still an unbalanced force, it will still move in one direction. The surfaces of the ground and or object isn’t smooth. Therefore creating difficulty when moving it.
A Balanced force will not move the object in any direction. This is because there is an equal amount of force being applied to all opposing sides. The net force will always equal 0 when there’s a balanced force!

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3 years ago

Where does secretion occur in the nephron?

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3 years ago

A 1.2516 gram sample of a mixture of caco3 and na2so4 was analyzed by dissolving the sample and completely precipitating the ca

Dennis_Churaev [7]

Answer:

0.009725 moles of H2C2O4

0.009725 moles CaCO3

Mass percentage = 77.77%

Explanation:

Step 1: The balanced equation

2MnO4- +5C2H2O4+6H+ →2Mn2+ +10CO2+8H2O

We can see that for 2 moles of Mno4- consumed , there is 5 moles of C2H2O4 needed and 6 moles H+ to produce 2 moles Mn2+, 10 moles of CO2 and 8 moles of H2O

Step 2: Calculate moles of MnO4-

Molarity = Moles/volume

Moles of Mno4- = Molarity of MnO4- * Volume of Mno4-

Moles of Mno4- = 0.1092M * 35.62 *10^-3 L

Moles of MnO4- = 0.00389 moles

Step 3: Calculate moles of H2C2O4

Since there is needed 5 moles of C2H2O4 to consume 2 moles of MnO4-

then for 0.00389 moles of MnO4-, there is 5/2 *0.00389 = 0.009725 moles of H2C2O4

Step 4: Calculate moles of CaCO3

moles of H2C2O4 = moles CaCO3, therefore, 0.009725 moles H2C2O4 = 0.009725 moles CaCO3

Step 5: Calculate mass of CaCO3

Molar mass of CaCO3 = 100.09 g/mole

Mass of CaCO3 = moles of CaCO3 * Molar mass of CaCO3

Mass of CaCO3 = 0.009725 moles * 100.09 g/mole = 0.9734 g

Step 6: Calculate percentage by weight of CaCO3

Mass of CaCO3 = 0.9734g

Mass of original sample = 1.2516g

Mass percentage = 0.9734/1.2516 *100% = 77.77%

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3 years ago

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valentinak56 [21]

Answer:

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Explanation:

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