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storchak [24]
1 year ago
7

A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC , is

on the x axis at x=0.500 m. (iii) Is there a point. at a finite distance where the electric potential is zero? (a) Yes; it is to the left of x=0 . (b) Yes; it is between x=0 and x=0.500m. (c) Yes; it is to the right of x=0.500m. (d) No.
Physics
1 answer:
ICE Princess25 [194]1 year ago
4 0

A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC, is on the x axis at x=0.500 m.

No, there is no point at a finite distance where the electric potential is zero.

Hence, Option D) is correct.

What is electric potential?

Electric potential is the capacity for doing work. In the electrical case, a charge will exert a force on some other charge and the potential energy arises. For example, if a positive charge Q is fixed at some point in space, any other positive charge when brought close to it will experience a repulsive force and will therefore have potential energy.

It is also defined as the amount of work required to move a unit charge from a reference point to a specific point against an electric field.

To learn more about electric potential, refer to:

brainly.com/question/15764612

#SPJ4

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The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be
eimsori [14]

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

  • 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
  • 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

6 0
2 years ago
A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
10. Discrimination refers to behaviors that
salantis [7]

Answer:

d)

Explanation:

the only one that makes sense

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PLEASE HELP!!! WILL MARK BRAINLIEST!! Name and define the four fundamental forces.
alukav5142 [94]

Answer:

Gravity.The weak force. Electromagnetism.The strong force.

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3 years ago
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Can someone help me in this one :)
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I believe it is “runs on parallel circuits”! my bad if incorrect
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