0.0034L
Explanation:
Given parameters:
Number of molecules of oxygen gas = 9.23 x 10¹⁹molecules
Unknown:
Volume of oxygen = ?
Solution:
Assuming the gas is at standard temperature and pressure conditions;
Volume of gas = number of moles x 22.4
we need to find the number of moles of the oxygen gas;
number of moles = ![\frac{number of particles}{6.02 x 10[tex]^{23}](https://tex.z-dn.net/?f=%5Cfrac%7Bnumber%20of%20particles%7D%7B6.02%20x%2010%5Btex%5D%5E%7B23%7D)
}[/tex]
Number of moles = ![\frac{9.23 x [tex]10^{19}](https://tex.z-dn.net/?f=%5Cfrac%7B9.23%20x%20%5Btex%5D10%5E%7B19%7D)
}{6.02 x 10
}[/tex]
Number of moles = 1.53 x 10⁻⁴moles
Volume of gas = 1.53 x 10⁻⁴ x 22.4 = 0.0034L
learn more:
STP brainly.com/question/12684384
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Time = distance/time
time(hours)= 10/40
time(hours)=0.25
=15 minutes
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A carbide ion is an anion of carbon atom with two carbon atoms with a triple bond connected to each other. Since this carbide ion is a negatively charged ion, in order to convert carbide ion to its neutral carbon atom, it has to give up/remove four electrons.
A: 0.7 -0.8 and 0hrs
B: 0.2 - 0.4 and 1.0 -1.1 hrs
C: 0-0.2 hrs and 0.8 - 1.0 hrs
D: 0.4 - 0.7 hrs
