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gavmur [86]
4 years ago
7

A sample of argon has a volume of 6.0 cm 3 and the pressure is 0.87 atm. If the final temperature is 35 degrees celsius, the fin

al volume is 10 cm 3 and the final pressure is 0.52 atm, what was the initial temperature of the argon
Chemistry
1 answer:
____ [38]4 years ago
3 0

Answer:

= 36.185 °C

Explanation:

Using the combined gas law;

P1V1/T1 = P2V2/T2

In this case;

P1 = 0.87 atm

V1 = 6.0 cm³

T1 = ?

P2 = 0.52 atm

V2 = 10 cm³

T2 = 35 °C + 273 = 308 K

Therefore;

T1 = P1V1T2/P2V2

   = ( 0.87 × 6.0 × 308)/( 0.52 ×10)

   = 309.185 K

Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C

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Answer:

through water

Explanation:

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3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . What is the theore
Masja [62]

Answer:

71g (assuming experimental data)

Explanation:

The balanced equation for this reaction:

H_{2} SO_{4}(aq) + 2NaOH (s) → Na_{2}SO_{4} (l) + 2H_{2} O (l)

Molar mass of H2SO4 = 98.1 g/mol

molar mass of NaOH = 40g/mol

Molar mass of Na2SO4 = 142.04g/mol

⇒ 1 mole or 98.1g of H2SO4 will yield 1 ole of NaSO4; alternately, 2 moles or 49 ×2 = 80g of NaOH produces 1 mole of NaSO4.

<em>Therefore, limiting reactant is NaOH.</em>

Assuming actual experiment is 20g of NaOH,

1 mole - 40g

x moles - 20g = \frac{20}{40} = 0.5 moles

⇒1 mole of Na2SO4 - 142.04g

∴ 0.5 moles = 142.04 × 0.5

<u>= 71.02g</u>

7 0
3 years ago
In the process of making soap, I poured some of the cooked mixture through some muslin fabric, in order to separate the solid pa
GenaCL600 [577]

Answer:

Filtering

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5 0
3 years ago
Virtually no chemical reaction can occur in the body in the absence of enzymes. how might excessively high body temperature or a
olchik [2.2K]
1. The structural unit of nucleic acids are composed of repeating units of monomers called nucleotides. Nucelotides are composed of three functional groups: sugars which are specifically pentoses (5-Carbon sugars), phosphate group and nitrogenous base.

2. The two major classes of nucleic acids in the body are the DNA or deoxyribonucleic acids and RNA or ribonucleic acids.

3.
a. Based on the nitrogenous bases and sugar, the DNA has a deoxyribose as the sugar and its 4 bases are adenine, guanine, cytosine and thymine. For RNA, the sugar is ribose while its 4 bases are <span>adenine, guanine, cytosine, and uracil

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8 0
3 years ago
How many grams of C are in 500g or NaHCO3​
harina [27]

Answer: 71.43g

Explanation: The RMM of NaHCO3 is

23+1+12+16(3)=84.

There is one carbon in NaHCO3 thus there are 1×12g of C in NaHCO3.

Thus

85gNaHCO3-----12g C

500gNaHCO3---- xgram

(500×12)÷84= 71.43

7 0
3 years ago
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