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gavmur [86]
3 years ago
7

A sample of argon has a volume of 6.0 cm 3 and the pressure is 0.87 atm. If the final temperature is 35 degrees celsius, the fin

al volume is 10 cm 3 and the final pressure is 0.52 atm, what was the initial temperature of the argon
Chemistry
1 answer:
____ [38]3 years ago
3 0

Answer:

= 36.185 °C

Explanation:

Using the combined gas law;

P1V1/T1 = P2V2/T2

In this case;

P1 = 0.87 atm

V1 = 6.0 cm³

T1 = ?

P2 = 0.52 atm

V2 = 10 cm³

T2 = 35 °C + 273 = 308 K

Therefore;

T1 = P1V1T2/P2V2

   = ( 0.87 × 6.0 × 308)/( 0.52 ×10)

   = 309.185 K

Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C

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Type the correct answer in the box. Express your answer to three significant figures.
VladimirAG [237]

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

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Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

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