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sladkih [1.3K]
4 years ago
7

A cloud of interstellar gas is rotating. Because the gravitational force pulls the gas particles together, the cloud shrinks, an

d, under the right conditions, a star may be formed. Would the angular velocity of the star be less than, greater than, or equal to the angular velocity of the rotating gas?
Equal to

Less than

Greater than
Physics
2 answers:
Sonja [21]4 years ago
6 0

Answer:

The answer is: Greater than.

Explanation:

It is well known that a gas cloud is very vast in relation to the diameter of the star, and that is why the angular momentum is maintained, the angular velocity must increase as size decreases. This is why the star will rotate much faster than the angular velocity of the gas cloud.

Fynjy0 [20]4 years ago
3 0

Answer:

Greater than

Explanation:

Here, angular momentum is conserved.

l_1\omega_1 =l_2\omega_2

When the cloud shrinks under the right conditions, a star may be formed.

Thus, Diameter of clouds are much higher than a star.

Moment of inertia of cloud is greater than the star's inertial.

so, angular velocity of the star would be greater than angular velocity of the rotating gas.

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A gas bottle contains 7.86×10^23 Oxygen molecules at a temperature of 327.0 K.
castortr0y [4]

Answer:

1.  E=5320.3J

2. E= 1773.45J

3. E=6.76*10^{-21}J

4. E=2.25*10^{-21}J

Explanation:

1. the thermal energy is given by the formula

E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J

where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.

2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

E_1=\frac{1}{2}NK_BT=1773.45J

3.

E=\frac{3}{2}K_BT=6.76*10^{-21}J

4.

E=\frac{1}{2}K_BT=2.25*10^{-21}J

Hope this helps!!

6 0
3 years ago
Human muscles have an efficiency of about
ryzh [129]

Answer: the answer is B. 18 to 26%

Explanation: I took the practice test on Edge and I got it right :)

8 0
3 years ago
Two charges that are 1 meter apart repel each other with a force of 2 N. If the distance between the charges is increased to 2 m
Savatey [412]

Answer:

b) 0.5 N

Explanation:

From coulomb's law,

F = kq'q/r².................... Equation 1

Where F =force of repulsion between the charges, q' = first charge, q = second charge, r = distance between the charges, k = proportionality constant.

q'q = Fr²/k........................... Equation 2

Given: F = 2 N, r = 1 m, k = 9.0×10⁹ Nm²/C²

Substituting into equation 2

q'q = 2(1)²/(9.0×10⁹)

q'q =  2/9.0×10⁹ C².

If the distance between the charges is increased to 2 meters,

r = 2 m, q'q = 2/9.0×10⁹ C².

Substitute into equation 1

F = 9.0×10⁹(2/9.0×10⁹)/2²

F = 2/4

F = 1/2 = 0.5 N.

The right option is b) 0.5 N

5 0
4 years ago
The loudness of a sound is determined by the __________, or height, of the sound wave.
NISA [10]

Answer: Aplitude

Explanation: Loudness depends on the amplitude,or height, of sound waves. The greater the amplitude, the louder the sound perceived. Amplitude is measured in decibels.

4 0
3 years ago
You hear the sound of the firing of a distant cannon 6.9 s after seeing the flash. how far are you from the cannon? (assume 343
EastWind [94]
Let's call d the distance of the cannon from us. We see the flash first, then after 6.9 s we hear the sound. The flash arrives to us traveling at speed of light, which is c=3 \cdot 10^8 m/s, while the sound travels at speed v=343 m/s. Since the magnitude of the  speed of light is much much larger than the speed of sound, we can assume that the flash arrives at our location instantaneously after the firing. 
Then we can say that the sound wave covers a distance d traveling at speed v in a time of t=6.9 s. Since it is a uniformly linear motion, the distance covered by the sound wave is
d=vt=(343 m/s)(6.9 s)=2367 m
So, this is the distance of the cannon from us.

6 0
3 years ago
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