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sladkih [1.3K]
4 years ago
7

A cloud of interstellar gas is rotating. Because the gravitational force pulls the gas particles together, the cloud shrinks, an

d, under the right conditions, a star may be formed. Would the angular velocity of the star be less than, greater than, or equal to the angular velocity of the rotating gas?
Equal to

Less than

Greater than
Physics
2 answers:
Sonja [21]4 years ago
6 0

Answer:

The answer is: Greater than.

Explanation:

It is well known that a gas cloud is very vast in relation to the diameter of the star, and that is why the angular momentum is maintained, the angular velocity must increase as size decreases. This is why the star will rotate much faster than the angular velocity of the gas cloud.

Fynjy0 [20]4 years ago
3 0

Answer:

Greater than

Explanation:

Here, angular momentum is conserved.

l_1\omega_1 =l_2\omega_2

When the cloud shrinks under the right conditions, a star may be formed.

Thus, Diameter of clouds are much higher than a star.

Moment of inertia of cloud is greater than the star's inertial.

so, angular velocity of the star would be greater than angular velocity of the rotating gas.

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Answer:

m = 5.22 kg

Explanation:

The force acting on the bucket is 52.2 N.

We need to find the mass of the bucket.

The force acting on the bucket is given by :

F = mg

g is acceleration due to gravity

m is mass

m=\dfrac{F}{g}\\\\m=\dfrac{52.2}{10}\\\\=5.22\ kg

So, the mass of the bucket is 5.22 kg.

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its d

Explanation:

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3 years ago
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94.35 meter

Step by step explanation

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A square plate of side 9 m is submerged in water at an incline of 60∘ with the horizontal. Its top edge is located at the surfac
Tpy6a [65]

Answer:

The force on one side of  the plate is 3093529.3 N.

Explanation:

Given that,

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Angle = 60°

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y=\dfrac{\Delta y}{\sin60}

y=\dfrac{2\Delta y}{\sqrt{3}}

The area of strip is

dA=\dfrac{9\times2\Delta y}{\sqrt{3}}

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Using formula of pressure

P=\dfrac{dF}{dA}

dF=P\times dA

On integrating

\int{dF}=\int_{0}^{9\sin60}{\rho g\times y\times 6\sqrt{3}dy}

F=9800\times6\sqrt{3}(\dfrac{y^2}{2})_{0}^{9\sin60}

F=9800\times6\sqrt{3}\times(\dfrac{(9\sin60)^2}{2})

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Answer:

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