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Brilliant_brown [7]

3 years ago

12

Should I apply for the Trusted Helpers Program? I want a real answer, if you don’t understand it don’t answer.

2 answers:

Svetradugi [14.3K]3 years ago

8 0

Yes you should if you will like to. It is your opinion so follow your dreams if they are your dreams.

Alex17521 [72]3 years ago

6 0

do what your heart tells you

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Consider the field E1 in the dielectric on the left of this interface. E1= 3ax+4ay+5az The interface lies in the z=0 plane. Find

denpristay [2]

Answer:

E₂ = 3ax +4ay + 2az

Interface angles ∅₁ = 45°

∅₂ = 68.20°

Explanation:

See the attached files for the calculation

7 0

3 years ago

The properties of metals depend mainly on the number and arrangement of neutrons<br> True<br> False

Sergeeva-Olga [200]

Answer:

False

Explanation:

Electrons

7 0

3 years ago

If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds

BabaBlast [244]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

According to above question ~

Current (I) = 4 Amperes

Time (t) = 3 seconds

Charge (q) = ?

Let's find the charge (q) by using formula ~

$I = \dfrac{q}{t}$

$4 = \dfrac{q}{3}$

$q = 4 \times 3$

$q = 12 \: \: coulombs$

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

7 0

3 years ago

A boy walked 4m east then 3m south find the displacement

Solnce55 [7]

Answer:

5m

Explanation:

$4^{2}+3^{2}=5^{2}\\5^{2}=25$

Use the Pythagorean theorem to calculate the long edge of the triangle, which would be his displacement.

3 0

2 years ago

Ilia_Sergeevich [38]

Answer:

The value is $C = 30729\ c$

Explanation:

From the question we are told that

The power rating of the stove is $P = 4.4 KW = 4.4 *10^{3} \ W$

The duration of its use everyday is $t_1 = 70 \ minutes = 1.167 \ hours$

The rating of the light bulbs is $P_2' = 150 W$

The number is $n = 7$

The power rating of the total bulb is $P_2 = 7 * 150 = 1050 \ W$

The duration of its use everyday is $t_2 = 7 hours$

The power rating of miscellaneous appliance $P_3 = 1.8 \ KW = 1.8 *10^{3} \ W$

The duration of its use everyday is $t_3 = 1 hour$

The power rating of hot water $P = 4 KW = 4 *10^{3} \ W$

The duration of its use everyday is $t_4 = 120 \ minutes = 2 hours$

Generally the total electrical energy used in 1 month is mathematically represented as

$E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30$

=> $E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30$

=> $E = 614598 \ W \cdot h$

=> $E = 614.6 \ K W \cdot h$

Generally the monthly electricity bill is mathematically represented as

$C = 614.6 * 50$

=> $C = 30729\ c$

8 0

2 years ago