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3 years ago

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2 answers:

4 0

A man pulls on a box with 50 N of applied force while another man pushes on the box from the opposite direction with 60 N of applied force. The box will stand still.

TRUE.

barxatty [35]3 years ago

4 0

Answer:

False statement.

Explanation:

It is given that,

Force with which a man pulls a box, F = 50 N (one side)

Force with which pushes on the box, F' = 60 N (in opposite direction)

The forces acting on the box are unbalanced. It means that the force acting in one side is more or less then force in other side. As a result the box will move.

So, the given statement is false.

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A single-turn circular loop of wire that has a radius of 3.5 cm lies in the plane perpendicular to a spatially uniform magnetic

Lena [83]

Explanation:

Given that,

Radius of the circular loop, r = 3.5 cm = 0.035 m

(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :

$\epsilon=-\dfrac{d(BA)}{dt}\\\\\epsilon=-\pi r^2\dfrac{B_f-B_i}{dt}\\\\\epsilon=-\pi (0.035)^2\dfrac{0.5-0.2}{0.12}\\\\\epsilon=-9.62\times 10^{-3}\ volts$

So, the magnitude of the emf induced in the loop during the time interval is $9.62\times 10^{-3}\ V$ .

(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.

5 0

3 years ago

How do whales bats and dolphins use echolocation?

g100num [7]

C is your answer ithink

3 0

3 years ago

Read 2 more answers

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the

lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0

3 years ago

At highway speeds, a particular automobile is capable of an acceleration of about 2.0 m/s2 . Part A At this rate, how long does

Natasha_Volkova [10]

Answer:

Time taken, t = 4.86 seconds

Explanation:

Given that,

Acceleration of a particular automobile, $a=2\ m/s^2$

Initial speed of the automobile, u = 75 km/h = 20.83 m/s

Final speed of the automobile, v = 110 km/h = 30.55 m/s

We need to find the time taken to accelerate from u to v. Let t is the time taken. It can be calculate as :

$t=\dfrac{v-u}{a}$

$t=\dfrac{30.55-20.83}{2}$

t = 4.86 seconds

So, the time taken by the automobile is 4.86 seconds. Hence, this is the required solution.

5 0

3 years ago

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A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.

Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

$\Delta p=m\Delta v=m(v_2-v_1)$

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

$\Delta p=F.\Delta t$

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

$\Delta p=14*0.06=0.84$

The change of momentum of the dart is 0.84 Nw.s

5 0

3 years ago