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dezoksy [38]
3 years ago
13

While competing in the Olympics, an athlete hurls a discus with a velocity of 31 m/s at an angle of 41. What is the vertical com

ponent of the discus's velocity?
Physics
2 answers:
ioda3 years ago
8 0
20.3 m/s I know it cause i was on apex looking for the answer because im stupid and got it wrong then it gave me the right answer
Alex787 [66]3 years ago
5 0

Answer:

vertical component of velocity is given as

v_y = 31 sin41 = 20.34 m/s

Explanation:

As we know that if a vector of a given magnitude is inclined at some angle with horizontal then its components with horizontal and vertical is given as

A_x = Acos\theta

A_y = Asin\theta

here vector is given as

v = 31 m/s

angle is given as

\theta = 41^0

now the vertical component is

v_y = 31sin41 = 20.34 m/s

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A rock is thrown from the top of a 20-m building at an angle of 53° above the horizontal. If the horizontal range of the throw
NemiM [27]

Answer:

28.5 m/s

18.22 m/s

Explanation:

h = 20 m, R = 20 m, theta = 53 degree

Let the speed of throwing is u and the speed with which it strikes the ground is v.

Horizontal distance, R = horizontal velocity x time

Let t be the time taken

20 = u Cos 53 x t

u t = 20/0.6 = 33.33 ..... (1)

Now use second equation of motion in vertical direction

h = u Sin 53 t - 1/2 g t^2

20 = 33.33 x 0.8 - 4.9 t^2     (ut = 33.33 from equation 1)

t = 1.17 s

Put in equation (1)

u = 33.33 / 1.17 = 28.5 m/s

Let v be the velocity just before striking the ground

vx = u Cos 53 = 28.5 x 0.6 = 17.15 m/s

vy = uSin 53 - 9.8 x 1.17

vy = 28.5 x 0.8 - 16.66

vy = 6.14 m/s

v^2 = vx^2 + vy^2 = 17.15^2 + 6.14^2

v = 18.22 m/s

6 0
3 years ago
Jasper and Gemma are going to play on a teeter totter. Gemma gets on first. When Jasper gets on, Gemma moves into the air, but s
Nezavi [6.7K]

Answer:

it will most likely be a: the forces are balanced because jasper weighs the same as gemma.

Explanation:

7 0
3 years ago
Read 2 more answers
How many oxygen (O) atoms are in a molecule of SiO2?<br> O A. 1<br> OB. 3<br> C. 4<br> D. 2
mafiozo [28]
I believe it is D. 2
3 0
3 years ago
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. A 40.0-kg child standing on a frozen pond throws a 0.500-kg stone to the east with a speed of 5.00 m/s. Neglecting friction be
tamaranim1 [39]

Answer:

Explanation:

A 40kg child throw stone of 0.5kg

At a direction of 5m/s

Recoil can be calculated using recoil of a gun formula

m_1•v_1 + m_2•v_2

m_1•v_1 = -m_2•v_2

The negative sign show that the momentum of the boy is directed oppositely to that of the stone

m_1 Is mass of boy

v_1 is the recoil velocity of the boy

m_2 is mass of stone

v_2 is the velocity of stone

Then,

m_1•v_1 = -m_2•v_2

40•v_1 = -0.5 × 5

40•v_1 = -2.5

v_1 = -2.5 / 40

v_1 = -0.0625 m/s

The recoil velocity of the boy is 0.0625 m/s

6 0
3 years ago
A boy got out of a boat and as he
emmainna [20.7K]

Answer:

third law of motion

Explanation:

6 0
4 years ago
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