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-BARSIC- [3]
3 years ago
14

Harry wrote the following examples of homeostasis:

Chemistry
2 answers:
Sveta_85 [38]3 years ago
8 0
The answer you seek is B.
Naddika [18.5K]3 years ago
5 0

Answer:

B.Example 2

Example 2: The kidney and other organs remove waste from the human body

Explanation:

Homeostasis is the maintenance of equilibrium. Kidneys regulate the volume and concentration of blood fluids, thus establishing homeostasis. Kidneys remove metabolic waste such as urea, uric acid, and excess sodium ions. Kidneys also help to balance the pH of the blood by secreting H⁺ and HCO₃⁻ ions.  

 

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belka [17]
<span>In the field of science, usually, the product of an experiment is computed ahead to understand if it reached a specific objective. It would reach greater than 100% of percent yield if the factors include faster reaction rates; proper handling of the reactants, no outside contaminants, and the procedure of the experiment is followed smoothly. It would reach lesser than 100% percent yield if the experiment is not followed, external factors such as contamination from the environment (wind, moisture, etc). </span>
8 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
2 years ago
Please, Give the correct answer ! Don't spam comment​
mars1129 [50]

Answer:

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Explanation:

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5 0
3 years ago
Other than exercises, what other factors do you think influences breathe/minute? <br>why?​
den301095 [7]

Answer:

I think probably diet because the type of food you put in your body (if it has high calorie or sodium) can severley affect your overall health and therefore affect your bpm(beats per minute)

Explanation:

5 0
3 years ago
Read 2 more answers
Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sa
Lapatulllka [165]

I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y, for the following reason: 

If you look at the combining masses of X and Y in each of the two compounds, 

The first compound contains 0.25g of X combined with 0.75g of Y 
so the ratio (by mass) of X to Y = 1 : 3 

The second compound contains 0.33 g of X combined with 0.67 g of Y 
so the ratio (by mass) of X to Y = 1 : 2 

Now, you suppose to prepare each of these two compounds, starting with the same fixed mass of element Y ( I will choose 12g of Y for an easy calculation!) 

The first compound will then contain 4g of X and 12g of Y 
The second compound will then contain 6g of X and 12g of Y 

<span>The ratio which combined the masses of X and the fixed mass (12g) of Y
= 4 : 6 
<span>or 2 : 3 </span>

So, the ratio of MOLES of X which combined with the fixed amount of Y in the two compounds is also = 2 : 3 </span>

The two compounds given with the plausible formula must therefore contain the same ratio.

8 0
3 years ago
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