Answer
given,
Initial speed of the car = 0 m/s
acceleration of car = 2.4 m/s²
Speed of the truck = 15.5 m/s
to car to overtake the truck distance travel by both should be same
distance traveled by the truck
d = 15.5 t
distance traveled by the car
d = u t + 1/2 gt ²
d = 0.5 x 9.8 t²
now, equating both the equations
15.5 t = 4.9 t²
t = 3.163 s
Time taken by car to overtake truck is 3.163 s
distance travel by the car = 15.5 x 3.163
d = 49 m
b) Speed of the automobile
using equation of motion
v = u + at
v = 0 + 2.4 x 3.163
v = 7.59 m/s
Speed of the automobile while crossing truck is equal to v = 7.59 m/s
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
So, the mass of the box is 71.42 kg.
Answer:
F = 11 N
Explanation:
Given,
Mass of a block, m = 5 kg
Acceleration of the block, a = 2.2 m/s²
We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :
F = ma
F = 5 kg × 2.2 m/s²
F = 11 N
So, the force on a person's hand is 11 N.
Electric force = electric field * charge
F = E*C => E = F / C = 0.047 N / 30 nC = 0.00157 N/nC = 0.00157 * 10^9 N/C = 1.57 * 10^6 N/C
