A small cylinder made of a diamagnetic material is brought near a bar magnet. One end of the cylinder is brought near the North
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Answer:
2.07 pm
Explanation:
The problem given here is the very well known Compton effect which is expressed as
here, is the initial photon wavelength,
is the scattered photon wavelength, h is he Planck's constant,
is the free electron mass, c is the velocity of light,
is the angle of scattering.
Given that, the scattering angle is,
Putting the respective values, we get
Here, the photon's incident wavelength is
Therefore,
From the conservation of momentum,
where, is the initial photon momentum,
is the final photon momentum and
is the scattered electron momentum.
Expanding the vector sum, we get
Now expressing the momentum in terms of De-Broglie wavelength
and putting it in the above equation we get,
Therefore,
This is the de Broglie wavelength of the electron after scattering.
Integrating the velocity equation, we will see that the position equation is:
Let the velocity of the particle is:
To get the position equation we just need to integrate the above equation:
Then:
Replacing that in our integral we get:
Where C is a constant of integration.
Now we remember that
Then we have:
To find the value of C, we use the fact that f(0) = 0.
C = -1 / 3
Then the position function is:
Integrating the velocity equation, we will see that the position equation is:
To learn more about motion equations, refer to:
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