Answer:
h f = Wf + K
where the total energy available is h f, Wf is the work function or the work needed to remove the electron and K is the kinetic energy of the removed electron 
If K = zero then hf = Wf
Wf = h f = h c / λ    or 
λ = h c / Wf = 6.63E-34 * 3.0E8 / (3.7 * 1.6E-19)
λ = 6.63 * 3 / (3.7 * 1.6) E-7 = 3.36E-7
This would be 3360 angstroms or 336 millimicrons
Visible light = 400-700 millimicrons
 
        
             
        
        
        
Explanation:
F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})
F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10
F = 900N
 
        
             
        
        
        
I’m sorry I don’t understand this language
        
             
        
        
        
Answer:
q2 = -1.61*10^-5 C.
Explanation:
It was given that,
 F = 0.985N
q1 = +8.40 X10-6 C
q2 = ?
r = 1.11 m
k = 9 x 10^9 (standard)
It generally follows that, if force is attractive, charge will be negative.
force, F = kq1q2/r^2
0.985 = 9*10^9*8.40*10^-6*q2/1.11^2
75600q2 = 0.985*1.11^2
 75600q2 = 1.2136
q2 = 1.2136/75600 = 1.60529
q2 = -1.61*10^-5 C.