Technician A says in a conventional transmission, the speed gears freewheel around the mainshaft until they are locked to it by
2 answers:
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Explanation:
The given data is as follows.
Length of beam, (L) = 5.50 m
Weight of the beam, () = 332 N
Weight of the Suki, () = 505 N
After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.
= 0
x =
=
= 0.986 m
Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.
Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.
Answer:
Explanation:
Check attachment for solution.
Generally the movement of the knight is L, i.e (2,1), (1,2),(-1,2),(1,-2) etc.
So using Pythagoras theorem
x^2+y^2=1^2+2^2
x^2+y^2=5
Then, the knight will make one movement when the displacement is √5.
So let take a look at other positions
(1,0),(0,1),(-1,0), (0,-1).
Then, for us to have this kind of movement, the knight has to make 3 movements.
When the displacement is 1, then it will make 3 movement.
Let examine other positions
(2,2) or(-2,-2) or (2,-2) or (-2,2)
When the displacement is √8
Then, the movement of the knight is 4.
Let examine other points
(2,0) or (0,2) or (-2,0) or (0,-2)
When the displacement is 2.
The knight make 2 movement
