Answer:
<h3>The answer is 0.79 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 2.56 g
volume = 3.25 mL
We have
We have the final answer as
<h3>0.79 g/mL</h3>
Hope this helps you
You will get iron sulfate and hydrogen sulfide gas (a.k.a. rotten egg gas).
FeS + H2SO4 = FeSO4 + H2S(g)
Change in Free Energy: ΔG(20C) = -66.6kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -37.3kJ (negative, so the reaction is exothermic)
Answer:
Explanation:
<u>1. Oxidation half-reaction (given)</u>
- 2S₂O₃²⁻ (aq) → S₄O₆²⁻ + 2e⁻
<u>2. Reduction half-reaction:</u>
Reduction is the gain of electrons with the consequent reduction in the number of oxidation.
The starting reactant is iodine which is diatomic; thus, it is I₂.
Each iodine atom gains one electron; thus, in total 2 electrons are gained and each I atom in solution will become an I⁻ anion.
Half-reaction:
- I₂ (aq) + 2e⁻ → 2I⁻(aq) ↔ answer
The overall reaction of thiosulfate anion with iodine is obtained when you add the two half-reactions:
- 2S₂O₃²⁻ (aq) → S₄O₆²⁻ + 2e⁻
===============================
(the electrons are canceled)
- 2S₂O₃²⁻ (aq) + I₂ (aq) → S₄O₆²⁻ + 2I⁻(aq)
The ammonia gas, having a lower molecular weight than the hydrogen chloride, will diffuse faster and travel a greater length of the tube. Consequently, the white ring of ammonium chloride will form much closer to hydrochloric acid end of the tube. Which in conclusion your answer will be D :)
Answer: Heat of reaction ∆H = -13.43kJ
Explanation:
The number of moles of NaOH = the number of moles of HCL = N
N = concentration × volume= CV = 0.5M × 500mL/1000ml/L
N= 0.5 × 0.5= 0.25mol
Since the Molar enthalpy is given by Hm = -53.72kJ/mol
Heat of reaction ∆H = N×Hm
∆H= 0.25mol × -53.72kJ/mol = -13.43kJ
Heat of reaction ∆H = -13.43kJ