b. 460.8 m/s
Explanation:
The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is
![f=\frac{v}{2L}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B2L%7D)
where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:
![v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s](https://tex.z-dn.net/?f=v%3D2Lf%3D2%280.90%20m%29%28256%20Hz%29%3D460.8%20m%2Fs)
c. 18,000 m
Explanation:
The relationship between speed of the wave, distance travelled and time taken is
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
v = 6,000 m/s is the speed of the wave
d = ? is the distance travelled
t = 3 s is the time taken
Re-arranging the formula and substituting the numbers into it, we find:
![d=vt=(6,000 m/s)(3 s)=18,000 m](https://tex.z-dn.net/?f=d%3Dvt%3D%286%2C000%20m%2Fs%29%283%20s%29%3D18%2C000%20m)
Answer:
6N
Explanation:
Given parameters:
Pressure applied by the woman = 300N/m²
Area = 0.02m²
Unknown:
Force applied = ?
Solution:
Pressure is the force per unit area on a body
Pressure =
Force = Pressure x area
Force = 300 x 0.02 = 6N
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU
Answer:
When two waves meet in such a way that their crests line up together, then it's called constructive interference. The resulting wave has a higher amplitude. In destructive interference, the crest of one wave meets the trough of another, and the result is a lower total amplitude.
The said development of the cell where the three cell layers help out do it is called as Gastrulation. The three layers - called as ectoderm, endoderm, and mesoderm - tend to form as this happens. This is a process that's present in all living things except sponges.