Question

What is the density (g/L) of NH3 at 105 kpa and 25 C ( 0.721 g/mol)?

Answer 1

Answer:

0.721 g/L

Explanation:

Ideal gas equation ->PV= nRT   ; n= mass (m)/ molar mass (M);

densitiy= mass (m)/ volume (V)

PV= (m/M)*RT  -> PVM= mRT   -> PM/RT= m/V   -> PM/RT=d

We need to put in SI units

105 Kpa= 1.04 atm

25°C= 298 K

d= (1.04 atm * 17 g/ mol)/(0.0821 * 298 K) = 0.721 g/L