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Dmitriy789 [7]
4 years ago
12

Under which conditions of temperature and pressure does a sample of neon behave most like an ideal gas?

Chemistry
2 answers:
jarptica [38.1K]4 years ago
4 0
Since real gases behave least ideally at low temperature and high pressure, they would behave most like an ideal gas at high temperature and low pressure.
 Therefore, (3) 400K and 0.25 atm is the correct answer.
Hope this would help~
Amanda [17]4 years ago
3 0

Answer : The correct option is, (3) 400 K and 0.25 atm

Explanation :

The conditions for ideal gas are :

Ideal gas are those gas that has no intermolecular attractions.

Ideal gas are those gas that have negligible volume.

The ideal gas equation is,

PV=nRT

The conditions for real gas are :

Real gas are those gas that have intermolecular attractions.

Real gas are those gas that have volume.

The real gas equation is,

(P+\frac{an^2}{V^2})(V-nb)=nRT

A real gas behave ideally at high temperature and low pressure condition.

From the given options, option (3) have high temperature and low pressure is the correct option.

Hence, the 400 K and 0.25 atm conditions of temperature and pressure does a sample of neon behave most like an ideal gas.

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What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
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Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

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What is the most appropriate unit of astronomical distance to represent the distance between an earth an orbiting space station
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. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
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