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3 years ago

What is a disadvantage of using biomass that the other types of alternative fuels do not have?

1 answer:

6 0

1)Agricultural wastes will not be available if the basic crop is no longer grown. 2)Additional work is needed in areas such as harvesting methods. 3)Land used for energy crops maybe in demand for other purposes, such as faming, conservation, housing, resort or agricultural use. 4)Some Biomass conversion projects are from animal wastes and are relatively small and therefore are limited. 5)Research is needed to reduce the costs of production of Biomass based fuels. 6)Is in some cases is a major cause of pollution.

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The formulas for elements never contain a subscript true or not true

Andru [333]

The answer should be false. Elements contain only one atom.

7 0

3 years ago

Determine the ph of a 0.18 m h2co3 solution. carbonic acid is a diprotic acid whose ka1 = 4.3 × 10-7 and ka2 = 5.6 × 10-11. dete

oee [108]

Answer is: ph value is 3.56.
Chemical reaction 1: H₂CO₃(aq) ⇄ HCO₃⁻(aq) + H⁺(aq); Ka₁ = 4,3·10⁻⁷.
Chemical reaction 2: HCO₃⁻(aq) ⇄ CO₃²⁻(aq) + H⁺(aq); Ka₂ = 5,6·10⁻¹¹.
c(H₂CO₃) = 0,18 M.
[HCO₃⁻] = [H⁺] = x.
[H₂CO₃] = 0,18 M - x.
Ka₁ = [HCO₃⁻] · [H⁺] / [H₂CO₃].
4,3·10⁻⁷ = x² / (0,18 M -x).
Solve quadratic equation: x = [H⁺] =0,000293 M.
pH = -log[H⁺] = -log(0,000293 M).
pH = 3,56; second Ka do not contributes pH value a lot.

5 0

3 years ago

You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions

artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0

3 years ago

A Metal pan will heat up quickly when placed over a gas or electric burner. The Metal pan is a good what...

Alik [6]

Answer:

heating up, lol

Explanation:

8 0

3 years ago

Magnesium has three naturally occurring isotopes(Mg-24, Mg-25, and Mg-26). The atomic mass and natural abundance of Mg-24 are 23

xxMikexx [17]

Answer:

The answer to your question is below

Explanation:

Data

Atomic mass Abundance

Mg -24 = 23.9850 79%

Mg -25 = 24.9858 10%

Mg - 26= ? ?

Process

1.- Find the abundance of Mg-26

The sum of the abundance of the three isotopes equals 100%

Abundance Mg-24 + Abundance-Mg-25 + Abundance-26 = 100

79 + 10 + Abundance-26 = 100

Abundance Mg-26 = 100 -89

Abundance Mg-26 = 11%

2.- Find the atomic mass of Mg-26, the average atomic mass is 24.31 amu

Average atomic mass = (abundance)(atomic mass- 24) + (abundance)

(atomic mass-25) + (abundance)(atomic mass-26)

24.31 = (0.79)(23.9850)+ (0.10)(24.9858) + (Atomic mass-26)(0.11)

24.31 = 18.94815 + 2.4986 + 0.11(atomic mass-26)

24.31 = 21.4342 + 0.11(atomic mass- 26)

0.11(atomic mass-26) = 24.31 - 21.4342

0.11(atomic mass-26) = 2.8758

Atomic mass-26 = 2.8758/0.11

Atomic mass-26 = 26.1436 amu

8 0

3 years ago

Read 2 more answers