Question

if an object accelerates from rest what will its velocity be after 12.3 s if it has a constant acceleration of 4.6 m/s

Answer 1

Answer:

56.6 m/s

Explanation:

The velocity of an object accelerating at constant acceleration is given by the following SUVAT equation

$v(t)=u+at$

where

u is the initial velocity

a is the acceleration

t is the time

For the object in the problem,

u = 0 since it starts from rest

$a=4.6 m/s^2$ is the acceleration

Substituting t = 12.3 s, we find the velocity at that time:

$v=0+(4.6)(12.3)=56.6 m/s$