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zvonat [6]
3 years ago
12

hen CO(g) reacts with O2(g) to form CO2(g) , 283 kJ of energy are evolved for each mole of CO(g) that reacts. Write a balanced t

hermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term (including the units) in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.
Chemistry
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

2CO + O2 =====> 2CO2          ΔH = -566 KJ

Explanation:

A thermochemical equation is a chemical equation that includes the enthalpy change of the reaction (Lumen Learning).

In a thermochemical equation, we can easily see the heat of reaction written after the symbols of reactants and products. It tells us whether heat was evolved or gained in the chemical process. When heat is gained ΔH = positive. When heat is evolved, ΔH = negative.

The thermochemical equation for the reaction of CO and O2 is shown below;

2CO(g) + O2(g) =====> 2CO2 (g)         ΔH = -566 KJ

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a) It allows electrons to flow from the anode to the cathode.

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dexar [7]

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5 0
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Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

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The pH of a solution is 3.81. What is the OH concentration in the solution?​
disa [49]

Answer:

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Explanation:

Step 1: Given data

pH of the solution: 3.81

Step 2: Calculate the pOH of the solution

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pOH = 14.00 - pH = 14.00 - 3.81 = 10.19

Step 3: Calculate the concentration of OH⁻ ions

We will use the definition of pOH.

pOH = -log [OH⁻]

[OH⁻] = antilog -pOH = antilog -10.19 = 6.46 × 10⁻¹¹ M

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3 years ago
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