Answer:
60 m
Explanation:
After 3 seconds of travel at 20 m/s, the projectile is 3·20 = 60 meters horizontally from the cannon.
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The vertical height after 3 seconds is 0.9 m, so the straight-line distance from cannon to target is √(60^2 +0.9^2) ≈ 60.007 meters.
The SI unit for density is
kg/m^3 or kilograms per meters cubed. (source: socratic.org)
Answer:
28.2 kg
Explanation:
Data provided in the question:
Mass of dog, m = 9.4 kg
Velocity of the dog with respect to water, v = 0.48 m/s
Velocity of the canoe, V = - 0.16 m/s [ - sign means velocity in opposite direction]
Now,
Let the mass of canoe be 'M'
Therefore,
From the conservation of momentum, we have
⇒ mv + MV = 0
or
⇒ 9.4 × 0.48 + M(- 0.16) = 0
or
⇒ 4.512 - 0.16M = 0
or
⇒ 0.16M = 4.512
or
⇒ M = 28.2 kg
relation between linear velocity and angular velocity is given as
here
v = linear speed
R = radius
= angular speed
now plug in all data in the equation
so rotating speed is 60.9 rad/s
The resultant in the x-direction:
Rx = F1 + F2 = 2.5 N - 1 N = 1.5 N .
The resultant in the y-direction:
Ry = F3 + F4 = 2 N - 3 N = -1 N.
