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yKpoI14uk [10]
4 years ago
15

Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n)

Physics
1 answer:
saveliy_v [14]4 years ago
4 0

Answer:

O is an element whilst H2O2 is a compound.

Explanation:

O is an element. You can find it on the periodic table. H2O2 is composed of both H and O. Thus, H2O2 is a compound.

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A wave with a wavelength of 15m travel at 330m/s.Calculate its frequency.​
katovenus [111]

ANSWER:

22 Hz.

Explanation:

Frequency = (speed) divided by (wavelength) = (330) / (15) =

8 0
3 years ago
A 0.54 kg particle has a speed of 5.0 m/s at point A and kinetic energy of 7.5 J at point B. What is
Wewaii [24]

<u>Answers</u>

(a)  6.75 Joules.

(b)  5.27 m/s

(c) 0.75 Joules


<u>Explanation</u>

Kinetic energy is the energy possessed by a body in motion.

(a) its kinetic energy at A?

K.E = 1/2 mv²

       = 1/2 ×  0.54 × 5²

       = 6.75 Joules.

(b) its speed at point B?

K.E = 1/2 mv²

7.5 = 1/2 × 0.54 × V²

V² = 7.5 ÷ 0.27

     = 27.77778

V = √27.77778

   = 5.27 m/s

(c) the total work done on the particle as it moves from A to B?

Work done = 7.5 - 6.75

                 = 0.75 Joules

4 0
3 years ago
A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
vredina [299]

Answer:

a) v_1=5.5172\ m.s^{-1}

b) v_2=-1.5152\ m.s^{-1}

c) v_3=4.6154\ m.s^{-1}

d) v_{avg}=3.8462\ m.s^{-1}

Explanation:

Given:

  • distance down the field in the first interval, d_1=16\ m
  • time duration of the first interval, t_1=2.9\ s
  • distance down the field in the second interval, d_2=-2.5\ m
  • time duration of the second interval, t_2=1.65\ s
  • distance down the field in the third interval, d_3=24\ m
  • time duration of the third interval, t_3=5.2\ s

a)

velocity in the first interval:

v_1=\frac{d_1}{t_1}

v_1=\frac{16}{2.9}

v_1=5.5172\ m.s^{-1}

b)

velocity in the second interval:

v_2=\frac{d_2}{t_2}

v_2=\frac{-2.5}{1.65}

v_2=-1.5152\ m.s^{-1}

c)

velocity in the third interval:

v_3=\frac{d_3}{t_3}

v_3=\frac{24}{5.2}

v_3=4.6154\ m.s^{-1}

d)

We know that the average velocity is given as the total displacement per unit time.

v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}

v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}

v_{avg}=3.8462\ m.s^{-1}

3 0
3 years ago
Please someone help
kari74 [83]
I can help you draw the ray diagram.
7 0
3 years ago
Rita places a 2.5 kg block on a frictionless inclined plane that is 30 degrees above horizontal. She applies a horizontal force,
vitfil [10]

Answer:

14.2

Explanation:

find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N

to prevent the sliding she needs to pull horizontally

Fh = 12.3 /Cos 30 =14.2N

7 0
3 years ago
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