E force needed to accelerate a 68 kilogram-skier at a rate of
1.2
m
s
2
is 81.6 Net forces.
Explanation:
Take the mass(68kg) and the acceleration of the skier(
1.2
m
s
2
) and multiply them together
Answer:
Please selection one of the following
Answer:
1) 51 m
2) Some energy was transformed to other forms. (This question)
3) 3.24 J
4) 45 J
5) 1020 J
Explanation:
100%
Answer: 247.67 V
Explanation:
Given
Potential At A 
Potential at 
when particle starts from A it reaches with velocity
at Point while when it starts from C it reaches at point B with velocity 
Suppose m is the mass of Particle
Change in Kinetic Energy of particle moving under the Potential From A to B

Change in Kinetic Energy of particle moving under the Potential From C to B

Divide 1 and 2 we get

on solving we get

