Answer :
The distance is 109.89 m.
Explanation :
Given that,
Height = 40 m
Angle = 20°
We need to calculate the base of the plateau
Using formula of angle

Where, h = height
x = base
= angle
Put the value into the formula



Hence, The distance is 109.89 m.
Answer:
6m/s
Explanation:
V = frequency * wavelength
15 * 2.5 = 6m/s
"Constant velocity" is another way of saying "zero acceleration".
The expression of the electric flux is

Here,
Q = Total charge enclosed in the closed surface
= Permittivity due to free space
Rearranging to find the charge,

Replacing with our values we have finally



The charge enclosed by the box is 0.1684nC
The sign of the charge can be decided by using the direction of the flux. The charge enclosed by the cube can be calculated by using the electric flux and the permitivity of free space.