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kolbaska11 [484]
3 years ago
12

Pleaseee helpppp meeeeeee I will give pountsss

Physics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

<h3>8. </h3>

m= 0. 113 kg

W = 1.1074 N

g = 9.8 m/ s²

<h3>9. </h3>

m= 870 kg

W = 8526 N

g = 9.8 m/s²

<h3>10.</h3>

a) weight on earth:

weight = mass × acceleration due to gravity (g)

<em>g</em><em> </em><em>on</em><em> </em><em>earth</em><em> </em><em>=</em><em> </em><em>9</em><em>.</em><em>8</em><em> </em><em>m</em><em>/</em><em>s</em><em>²</em>

W = 75 × 9.8

<u>W</u><u> </u><u>= </u><u>7</u><u>3</u><u>5</u><u> </u><u>N</u>

b) g on Mars

285 = 75 × g

g = 285/ 75

<u>g = 3.8 m/ s²</u>

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You drop a 0.375 kg ball from a height of 1.37 m. It hits the ground and bounces up again to a height of 0.67 m. How much energy
Radda [10]

2.57 joule energy lose in the bounce .

<u>Explanation</u>:

when ball is the height of 1.37 m from the ground  it has some gravitational potential energy with respect to hits the ground  

Formula for gravitational potential energy given by  

Potential Energy = mgh

Where ,

m = mass  

g = acceleration due to gravity  

h = height

Potential energy when ball hits the ground

m= 0.375 kg

h = 1.37 m

g = 9.8 m/s²

Potential Energy = 0.375\times9.8\times1.37

Potential Energy = 5.03 joule

Potential energy when ball bounces up again

h= 0.67 m

Potential Energy = 0.375\times0.67\times9.8

Potential Energy = 2.46 joule

Energy loss = 5.03 - 2.46 = 2.57 joule

2.57 joule energy lose in the bounce

6 0
3 years ago
Please help with this!!!!!
34kurt
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3 years ago
A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.
Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, q_1=9\ \mu C=9\times 10^{-6}\ C

Charge on sphere 2, q_1=4\ \mu C=4\times 10^{-6}\ C

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{9\times 10^{-6}\times 4\times 10^{-6}}{(0.06)^2}

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So, the electrical force between them is 90 N. Hence, this is the required solution.

7 0
3 years ago
The histogram below shows the number of downloads of a song over time.
Allisa [31]

Given data:

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  • A diagram consists rectangles, whose area is proportional to frequency of a variable and whose width is equal to the class interval.
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<em>From Figure:</em>  

        Each box in the graph (small rectangle box) is assumed to be one download. So, in the graph the time between 8 p.m to 9 p.m, the number of downloads are 8.75 approximately (because the last box is incomplete, therefore 8 complete boxes and 9th is more than half).

<em>So, We conclude that the total number of downloads are approximately 9 in the time span of 8 p.m. to 9 p.m.</em>

7 0
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An igneous intrusion whose boundaries lie parallel to the layering in the surrounding country rock is considered to be:
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