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faltersainse [42]
3 years ago
11

A boy, standing at point O, is whirling a ball on a string over his head. After several whirls, he lets go of the string and the

ball travels in a straight line. Describe the velocity of the ball in both situations: whirling overhead and being let go.
Physics
2 answers:
allsm [11]3 years ago
8 0

D)While whirling overhead, the velocity changes. Moving in a straight line, the velocity does not change.

kirza4 [7]3 years ago
4 0
While the ball is <span>whirling overhead it is moving in a circle. It has circular velocity. More often used term is angular velocity. This comes from the fact that ball travels some angle during some time.

When it is let go ball travels in a straight line. It has linear velocity. Word "linear" means "straight".</span>
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Why is the cycle of cellular respiration and photosynthesis important to life for plants
devlian [24]
The cycle of cellular respiration and photosynthesis are important for the life of plants because cellular respiration uses one of the products of photosynthesis (oxygen), and uses it as one of the reactants along with glucose to produce carbon dioxide. These two cycles help maintain a balance for our atmosphere, even though pollution and other factors have disrupted this balance. Hope this helps! :)
5 0
3 years ago
A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. T
Nina [5.8K]

Answer:

a)5.88J

b)-5.88J

c)0.78m

d)0.24m

Explanation:

a) W by the block on spring is given by

W= \frac{1}{2}kx² = \frac{1}{2}(530)(0.149)² =  5.88 J

b)  Workdone by the spring = - Workdone by the block = -5.88J

c) Taking x = 0 at the contact point we have U top = U bottom

So, mgh_o = \frac{1}{2}kx² - mgx

And, h_o= ( \frac{1}{2}kx² - mgx )/(mg) = [\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)]/(0.645x9.8)    

   h_o=   0.78m            

d) Now, if the initial initial height of block is 3h_o

h_o = 3 x 0.78 = 2.34m

then, \frac{1}{2}kx² - mgx - mgh_o =0

 

\frac{1}{2}(530)x²  - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0

265x² - 6.321x - 14.8 = 0  

a=265

b=-6.321

c=-14.8

By using quadratic eq. formula, we'll have the roots

x= 0.24 or x=-0.225

Considering only positive root:

x= 0.24m (maximum  compression of the spring)

4 0
3 years ago
A wheel with a weight of 388 N comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it i
Alisiya [41]

the correct answer is 14m

4 0
3 years ago
A 92.6 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large piece of chocolate cake rated at 735 (
Kitty [74]

Answer:

349 m

Explanation:

Parameters given:

Mass of climber, m = 92.6 kg

Amount of food calories = 735

1 food calorie = 103 calories

735 food calories = 75705 calories

1 joule is equal to 0.239 calories. Therefore, 75705 calories will be 316749.72 joules.

Hence, this is the amount of work the climber must do work off the food he ate.

Work done is given as:

W = Force * distance

W = m * g * h

h = W/(m * g)

h = 316749.72/(92.6 * 9.8)

h = 349 m

4 0
3 years ago
3/10
lyudmila [28]

Answer:

4,800?

First I subtracted 8 from 24 because there are 24 hours in a day ad she spends 8 of those hours sleeping. I then took the answer which was 16, and multiplied that by 60 to find out how many minutes were in 16 hours and I got 960. I then multiplied 960 by 5 because she winks 5 times each minute. This left me with the answer 4,800.

7 0
3 years ago
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