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faltersainse [42]

3 years ago

11

A boy, standing at point O, is whirling a ball on a string over his head. After several whirls, he lets go of the string and the

ball travels in a straight line. Describe the velocity of the ball in both situations: whirling overhead and being let go.

2 answers:

allsm [11]3 years ago

8 0

D)While whirling overhead, the velocity changes. Moving in a straight line, the velocity does not change.

kirza4 [7]3 years ago

4 0

While the ball is <span>whirling overhead it is moving in a circle. It has circular velocity. More often used term is angular velocity. This comes from the fact that ball travels some angle during some time.

When it is let go ball travels in a straight line. It has linear velocity. Word "linear" means "straight".</span>

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A small oil droplet is sprayed between the plates of a parallel plate capacitor. The droplet has a net charge equal to that of 3

masha68 [24]

Answer:

…..

Explanation:

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6 0

2 years ago

A long wire carries a current toward the north in a magnetic field that is directed vertically downward perpendicular to the sur

xenn [34]

The direction of the magnetic force on the wire is west.

The magnetic force acting on the moving protons acts northward in the horizontal plane. If the thumb is up (current flows vertically up), the wrapped finger will be counterclockwise.

Therefore, the direction of the magnetic field is counterclockwise. Here, the magnetic field is pointing upwards (vertical magnetic field) and the electrons are moving east. Applying Fleming's left-hand rule here, we can see that the direction of force is along the south direction.

As the change in magnetic flux increases upwards, Lenz's law indicates that the induced magnetic field of the induced current must resist and the inside of the loop must be directed downwards. Using the right-hand rule, we can see that a clockwise current is induced.

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3 0

2 years ago

Read 2 more answers

A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 1.00 m/s when it starts to rain with i

bija089 [108]

Answer:

$v_o\approx0.7059\ m.s^{-1}$

Explanation:

Given:

mass of the boat, $m=120\ kg$

uniform speed of the boat, $v=1\ m.s^{-1}$

rate of accumulation of water mass in the boat, $\dot m=100\ kg.hr^{-1}$

time of observation, $t=0.5\ hr$

The mass of the boat after the observed time:

$m_o=m+\dot m\times t$

$m_o=120+100\times 0.5$

$m_o=170\ kg$

<u>Now using the conservation of momentum:</u>

$m.v=m_o.v_o$

$120\times 1=170\times v_o$

$v_o\approx0.7059\ m.s^{-1}$

4 0

3 years ago

How much energy is required to ionize hydrogen when it is in the n = 5 state?

PtichkaEL [24]

Answer:

0.544 eV

Explanation:

To ionize the hydrogen atom $n_f\rightarrow infinte$

So the required energy is $\Delta E=13.6(\frac{1}{n_i^2}-\frac{1}{n_f^2})$ as $n_f\rightarrow infinte$

So $\Delta E=13.6\frac{1}{n_i^2}$

We have to calculate the energy required to ionize hydrogen atom when it is in n=5

So the energy should be less than $\Delta E=13.6\frac{1}{5^2}=0.544eV$

4 0

3 years ago

The fastest measured pitched baseball left the pitcher's hand at a speed of 42.0 m/s. If the pitcher was in contact with the bal

I am Lyosha [343]

Answer:

The acceleration and time are 588 m/s² and 0.071 sec respectively.

Explanation:

Given that,

Speed = 42.0 m/s

Distance = 1.50 m

(a). We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

$a=\dfrac{v^2-u^2}{2s}$

Put the value in the equation

$a=\dfrac{42.0^2-0}{2\times1.50}$

$a=588\ m/s^2$

(b). We need to calculate the time

Using equation of motion

$v = u+at$

$t=\dfrac{v-u}{a}$

$t=\dfrac{42.0-0}{588}$

$t=0.071\ sec$

Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.

8 0

3 years ago