Answer:
0.231 N
Explanation:
To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be
If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:
According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is
So the force acting on the other end to generate this torque mush be:
Down to the left, down the the right, criss cross!
Answer:
Explanation:
This problem is all about torque. The "rules" are that in order for a system to be in rotational equilibrium, the sum of the torques on the system have to equal 0 (in other words, they have to equal each other {cancel each other out}). The equation for torque is
τ = F⊥r where τ is torque, F⊥ is the perpendicular force, and r is the lever arm length in meters. We also have to understand that in general Forces moving clockwise are negative and Forces moving counterclockwise are positive. Now we're ready for the problem:
A. The counterclockwise torque:
τ = 300(3) so
τ = 900N*m
B. The clockwise torque:
τ = -450(2.5) so
τ = -1100N*m
C. Obviously the system is not in roational equilibrium because one side is experiencing a greater torque than the other. This system will move clockwise as it currently exists.
D. In order for the system to be in rotational equilibrium, we have to move Bob's location from the fulcrum. Let's see to where.
The torques have to be the same on both sides of the fulcrum; mathematically, that looks like this:
F⊥r = F⊥r Filling in:
300(3) = 450r and
900 = 450r so
2 = r. This means that Bob will have to move closer to the fulcrum by a half of a meter to 2 meters from the fulcrum in order for the system to be in balance.
Isn't this so much fun?!
<span>Number of Protons/Electrons: 80
Number of Neutrons: 121</span>
