Answer:
5m/s2
Explanation:
Data obtained from the question include:
m (mass) = 2000 kg
F (force) = 10000N
a (acceleration) =?
Using the formula F = ma, the acceleration of the truck can be obtained as follow:
F = ma
a = F/m
a = 10000/2000
a = 5m/s2
The acceleration of the truck is 5m/s2
Answer:
a) E = 1.47 × 10^5 N/C
b) south
Explanation:
The magnitude of an electric field can be defined mathematically as;
E = F/q ........1
Where,
E = magnitude of the electric field
F = electric force
q = charge on the proton
Given;
F = 2.36 × 10^-14 N
Note that charge on a proton is known as Qp = 1.602 × 10^-19 C
q = 1.602 × 10^-19 C
Substituting into equation 1, we have;
E = 2.36 × 10^-14 N/1.602 × 10^-19 C
E = 1.47 × 10^5 N/C
b) The direction of the electric field;
From equation 1
E = F/q ........1
since both electric field and electric force are vector quantity and q is a positive charge (constant), then both the electric field and electric force would be parallel to each other. Therefore the electric field is directed to the south also.
(When a vector is multiplied by a positive constant the direction remains the same)
Answer:
b. 
Explanation:
As we know that the electric field due to infinite line charge is given as
here we can find potential difference between two points using the relation
now we have
now we have
now plug in all values in it
now we know by energy conservation
Answer:
Explanation:
Linear momentum of the block is conserved in the 
direction since the impulsive force due to impact cancels each other internally.
Using the conservation of energy to the block system considering the initial position:
Applying Sine rule:
Hence, the distance the block will slide up is 6.874mm
