A crowd in a stadium is heard by a man standing 823.2 m away. The man hears the noise

Physics

1 answer:

Reil [10]3 years ago

8 0

Answer: 329.28 m/s

Explanation:

Given that:

Distance of sound = 823.2 m

Time taken for sound = 2.5 seconds

The speed of traveling sound = ?

Speed is obtained by dividing the distance travelled by the time taken for the travel.

Speed = Distance / time

Speed = 823.2m/2.5 seconds

Speed = 329.28 m/s

Thus, the sound traveling as fast as 329.28 m/s

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A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied

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We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the book is

F=44N

From the question we are told

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the Force is mathematically given as

$F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\$