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3 years ago

A crowd in a stadium is heard by a man standing 823.2 m away. The man hears the noise

Physics

1 answer:

Reil [10]3 years ago

8 0

Answer: 329.28 m/s

Explanation:

Given that:

Distance of sound = 823.2 m

Time taken for sound = 2.5 seconds

The speed of traveling sound = ?

Speed is obtained by dividing the distance travelled by the time taken for the travel.

Speed = Distance / time

Speed = 823.2m/2.5 seconds

Speed = 329.28 m/s

Thus, the sound traveling as fast as 329.28 m/s

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How does a message travel across the gap at a synapse?

IRINA_888 [86]

It's sent through neurotransmitters.

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4 years ago

-In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The fo

vampirchik [111]

Answer:

$4.3859007196\times 10^{-9}\ m$

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

v = Velocity of electron = $2.4\times 10^5\ m/s$

q = Charge of electron = $1.6\times 10^{-19}\ C$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

r = Radius

The electrical and centripetal force will balance each other

$\dfrac{kq^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{kq^2}{mv^2}\\\Rightarrow r=\dfrac{8.99\times 10^9\times (1.6\times 10^{-19})^2}{9.11\times 10^{-31}\times (2.4\times 10^5)^2}\\\Rightarrow r=4.3859007196\times 10^{-9}\ m$

The radius of the orbital is $4.3859007196\times 10^{-9}\ m$

4 0

3 years ago

Find the work w1 done on the block by the force of magnitude f1 = 65.0 n as the block moves from xi = -3.00 cm to xf = 3.00 cm .

inn [45]

W = F•dx
F = 65 N,
dx = xf - xi = 0.03 m - (-0.03 m) = 0.06 m
W = 65 N × 0.06 m = 3.9 J

5 0

3 years ago

A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 17.3 m/s directly upward.

elena-s [515]

Answer:

h=15.27m

Explanation:

Since at maximum height the vertical velocity must be null it's better to use the formula:

$v_f^2=v_i^2+2ad$

We will use this formula for the vertical direction, choosing the upward direction as the positive one, so we have:

$0=v_i^2+2ah$

$h=-\frac{v_i^2}{2a}$

which for our values is:

$h=-\frac{(17.3m/s)^2}{2(-9.8m/s^2)}=15.27m$

7 0

3 years ago

A spinning disc rotating at 130 rev/min slows and stops 31 s later. how many revolutions did the disc make during this time?

gayaneshka [121]

F = 130 revs/min = 130/60 revs/s = 13/6 revs/s
t = 31s
wi = 2πf = 2π × 13/6 = 13π/3 rads/s
wf = 0 rads/s = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 rads/s²
wf² - wi² = 2a∅
-169π²/9 rads²/s² = 2 × -13π/93 rads/s² × ∅
∅ = 1209π/18 rads
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.

3 0

3 years ago