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Vera_Pavlovna [14]
3 years ago
11

Which is more reactive, Rubidium or Hydrogen?

Chemistry
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:rubidium is the second most reactive metal so it is more reactive than hydrogen

Explanation:

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Ill give brainlists
Ronch [10]

I think B would be the right answer, because knowing the feedback of results of the insecticide would give you more knowledge on which one would be less dangerous for animals and children.

3 0
3 years ago
A gas at 20.0°C is increased to 40.0°C, will its volume: if the original volume is 1.00 l, what would the new volume be
Leona [35]

Answer:

2.0 l

Explanation:

When for 20 °C volume is 1 l then for 40°C is going to be 2 l

20-------1

40-------x

x=(40*1):20

6 0
3 years ago
A 1.775g sample mixture of potassium hydrogen carbonate is decomposed by heating. if the mass loss is 0.275g what is the percent
Marina86 [1]

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

  • Step 1: Write the balanced equation for the decomposition of KHCO₃.

2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)

The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.

  • Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.

In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.

0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃

  • Step 3: Calculate the mass percentage of KHCO₃ in the sample.

There are 1.25 g of KHCO₃ in the 1.775 g sample.

%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

Learn more about decomposition reactions here: brainly.com/question/14219426

7 0
2 years ago
Find the energy of a photon of light if the wavelength of the light wave is 6.88 x 10–7m
stepan [7]
Use the formula E=hv, h=plancks constant and v=frequency
use the formula c=v*lambda to find v
the answer will be 2.88*10^-23J

6 0
3 years ago
At 500 K, the reaction is at equilibrium with the following concentrations. [PCI5]= 0.0095 M [PCI3] = 0.020 [CI2] = 0.020 M What
Ad libitum [116K]
Although it is omitted, the reaction equation for the decomposition of phosphorus pentachloride is:
PCl₅ → PCl₃ + Cl₂

The equilibrium constant's equation then becomes:
Kc = [PCl₃]*[Cl₂] / [PCl₅]
Kc = (0.02 * 0.02) / 0.0095
Kc = 0.042

The equilibrium constant is 0.042.
8 0
3 years ago
Read 2 more answers
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