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3 years ago

How are sound waves and EM waves alike? How are they different?

1 answer:

5 0

Sound waves are longitudinal waves that is, are transmitted in the same direction of oscillation of the particles in the medium. Electromagnetic waves are transverse ie, the electric and magnetic fields, which are perpendicular to each other, oscillate perpendicularly to the direction of wave propagation.

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A monoprotic weak acid, HA , dissociates in water according to the reaction:

Ratling [72]

<u>Answer:</u> The $pKa$ of the acid is 6.09

<u>Explanation:</u>

For the given chemical reaction:

$HA(aq.)\rightleftharpoons H^+(aq.)+A^-(aq.)$

The expression of equilibrium constant [tex[(K_a)[/tex] for the above equation follows:

$K_a=\frac{[H^+][A^-]}{[HA]}$

We are given:

$[HA]_{eq}=0.200M$

$[H^+]_{eq}=4.00\times 10^{-4}M$

$[A^-]_{eq}=4.00\times 10^{-4}M$

Putting values in above expression, we get:

$K_a=\frac{(4.00\times 10^{-4})\times (4.00\times 10^{-4}}{0.200}\\\\K_a=8.0\times 10^{-7}0$

p-function is defined as the negative logarithm of any concentration.

$pKa=-\log(K_a)$

So,

$pKa=-\log(8.0\times 10^{-7})\\\\pKa=6.09$

Hence, the $pKa$ of the acid is 6.09

7 0

4 years ago

1. For each of the following, convert the word equation into a formula equation, BUT do not balance! (4 pts each = 12 pts)

daser333 [38]

Answer:

1a) BaClO₃(s) → BaCl₂(g) + O₂(g)

1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

2a) Calcium hydroxide and hydrogen gas

2b) Tin(II) silicate and Lead(IV) permanganate

2c) Magnesium oxide and water

2d) No product

2e) Mercury and iodine

2f) Calcium chloride and iodine

2g) Strontium phosphite and cesium nitride

2h) Carbon dioxide, water, and sulfur dioxide

2i) Iron oxide(III) and carbon dioxide

2j) Magnesium acetate and hydrogen gas

2k) Calcium iodide

Explanation:

1. For each of the following, convert the word equation into a formula equation, BUT do not balance!

a) Barium chlorate → Barium chloride + Oxygen

<u>1. Chemical formulas</u>

Barium chlorate:

It is a salt: an ionic compound.
Barium has oxidation state +2
Chlorate is the ion ClO₃⁻
Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
Chemical formula Ba(ClO₃)₂
It is solid: Ba(ClO₃)₂(s)

Barium chloride:

It is a salt: an ionic compount
Barium has oxidation state +2
Chlorine is in oxidation state -1
Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
BaCl₂
It is solid BaCl₂(s)

Oxygen:

It is a diatomic gas molecule
O₂(g)

<u />

<u>2. Write the unbalanced molecular equation:</u>

BaClO₃(s) → BaCl₂(s) + O₂(g)

b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride

<u>1. Chemical formulas</u>

Chlorine:

It is a diatomic gas molecule
Cl₂(g)

Potassum nitride

It is a salt

Potassium has oxidation state +1
Nitrogen is with oxidation state +3
Swap the oxidation states
K₃N
It is solid: K₃N(s)

Nitrogen:

It is a diatomic gas
N₂(g)

Potassium chloride

It is a salt (ionic compound)
Potassium has oxidation state +1
Chlorine is in oxidation state -1
Swap the oxidation numbers
KCl
It is solid: KCl(s)

<u>2. Write the unbalanced molecular equation</u>

<u />

Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate

<u>1. Chemical formulas</u>

Sodium nitride

It is a salt (ionic compound)
Sodium has oxidation state +1
Nitrogen is with oxidation state -3
Swap the oxidation numbers
Na₃N
It is in aqueous solution
Na₃N (aq)

Aluminum bromate

Salt
Aluminum has oxidation state +3
Bromate is the ion BrO₃⁻
Swap the oxidation states
Al(BrO₃)₃ (aq)

Aluminum nitride

Both Al and N have oxidation state 3, which simply
AlN(s). It is not soluble in water.

Sodium bromate

Na(BrO₃)₃ (aq)

<u>2. Write the unbalanced molecular equation</u>

Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

<h2>This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2></h2><h2>The attached file contains the complete answer.</h2>

Download pdf

4 0

4 years ago

What is the volume of an object with the height of 2cm, a width of 4cm, a mass of 20g, and a length of 5cm?

kotegsom [21]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

At 50 degrees celcius and standard pressure intermolecular forces of attraction are strongest in a sample of

Ivanshal [37]

At 50 degrees Celsius and standard pressure inter-molecular forces of attraction are strongest in a sample of ethanoic acid.
Ethanoic acid has hydrogen atom bonded with a more electronegative atom; Oxygen. As a result, the molecule possesses strong intermolecular Hydrogen Bonds. Therefore; ethanoic acid, and all other carboxyllic acids have the tendency to form dimers.

4 0

3 years ago

Read 2 more answers

Explain why the equation ( x - 4 ) ^2 - 28 =8 has two solutions. Then solve the equation to find the solutions. Show your work.

algol13

Taking into account the discriminant and quadratic formula:

As Δ> 0 the function has two real roots or solutions.
The solutions are x1= 10 and x2= -2.

<h3 />

Zeros or solutions of a function

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, the zeros represent the roots of the polynomial equation that is obtained by making f(x)=0.

In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

<h3>Discriminant</h3>

The function f(x) = ax² + bx + c

with a, b, c real numbers and a ≠ 0, is a function quadratic expressed in its polynomial form (It is so called because the function is expressed by a polynomial).

The following expression is called discriminant:

Δ= b²- 4×a×c

The discriminant determines the amount of roots or solutions of the function.

Then:

If Δ <0 the function has no real roots and its graph does not intersect the x-axis.
If Δ> 0 the function has two real roots and its graph intersects the x-axis at two points.
If Δ = 0 the function has a real root and its graph intersects the x-axis at a single point that coincides with its vertex. In this case the function is said to have a double root.

<h3 /><h3>Amount of solutions of function (x - 4)² - 28 =8</h3>

The function (x - 4)² - 28 =8 can be expressed as:

(x - 4)² - 28 -8= 0

(x - 4)² - 36= 0

x²- 8x + 16 - 36= 0

x²- 8x - 20= 0

Being: