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3 years ago

Mike has swelling in his nasal and sinus tissues. What type of medication will help him with this condition?

1 answer:

6 0

Aromatherapy based treatment can offer impermanent help when nasal and sinus tissue drainage blockage and pressure for Mike.

Explanation:

Nasal and sinus tissues provide stuffy nose and pain or pressure in several areas around the face or teeth. There's normally a nasal release that might be yellow, green, or clear. You may likewise have exhaustion, the issue with a feeling of smell or taste, hack, sore throat, terrible breath, migraine, torment when you twist forward, and fever.

For this issue, Mike can utilize Aromatherapy based treatment that can offer some quick help with discomfort on the blocked nose and migraine. During this stage, mike ought to breathe in some restorative or common smell to control his sufferings. Fragrance, for example, Peppermint, Eucalyptus, Tea tree, Oregano, Clary wise, Lavender, Rosemary, and so forth are a great idea to breathe in.

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Pls help i’ll give brainliest if you give a correct answer!!

arsen [322]

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

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3 years ago

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A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?

Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

$I=\frac{Q}{t}$

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

I= 19500 A
Q=36 C
t=?

Replacing:

$19500 A=\frac{36 C}{t}$

Solving:

19500 A*t= 36 C

$t=\frac{36 C}{19500 A}$

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

Its duration is 1.85*10⁻³ s or 1.85 ms

8 0

3 years ago

3. How does the mass of a proton compare to the mass of an electron?

o-na [289]

Answer:

Proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.

7 0

3 years ago

Earth's gravitational force just got three times stronger! What happens to your weight?

kicyunya [14]

Your "weight" is the name you give to that gravitational force.
So your question actually says:

"Your weight just got three times stronger !
What happens to your weight ?"

8 0

3 years ago

Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2

aleksandr82 [10.1K]

Answer:

The curl is $0 \hat x -z^2 \hat y -4xy \hat z$

Explanation:

Given the vector function

$\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z$

We can calculate the curl using the definition

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|$

Thus for the exercise we will have

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|$

So we will get

$\nabla \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z$

Working with the partial derivatives we get the curl

$\nabla \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z$

6 0

4 years ago