The answer would just be:
<span>Tungsten
</span>hope that this helps you! =)
The stock solution contains 10.5 moles of HCl per litre. A 5.5 litre solution of 2.5M HCl contains 5.5x2.5 = 13.75moles of HCl. Since every litre of stock solution provides 10.5M HCl, the amount of stock solution needed is 13.75/10.5 = 1.309L. Therefore you would dilute 1.309L of stock solution to 5.5L
Temperature of somewhere.
Answer:
difficult to answer, need a bit more detail
