Answer:
Correct answer: F₂ = 104.5 N
Explanation:
Given:
m = 57 g = 57 · 10⁻³ kg
Δt = 30 ms = 30 · 10 ⁻³ seconds
V₁ = 73.14 m/s service speed
V₂ = 55 m/s returned speed
M = m · V Momentum or Impulse
You forgot to indicate what time the ball contact when returning.
We will assume that the time is the same Δt = 30 ms = 30 10 ⁻³ seconds.
The formula for calculating force is according to Newton's second law is:
F = ΔM / Δt = m · ΔV / Δt
Force during service is:
F₁ = 57 · 10⁻³ · 73.14 / 30 · 10 ⁻³ = 138.97 N
F₁ = 138.97 N
Returned force:
F₂ = 57 · 10⁻³ · 55 / 30 · 10 ⁻³ = 104.5 N
F₂ = 104.5 N
God is with you!!!
Answer:

Explanation:
since force is applied downwards at some angle with the horizontal
so here we will have

now we know that the box will not move if applied force is balanced by frictional force on it
so we will have




so here we can say





Answer:
43,555 W
Explanation:
Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

where
m = 1000 kg is the mass
is the acceleration due to gravity
So,

Then the work done in lifting the equipment is:

where
d = 200 m is the displacement of the equpment
Substituting,

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

where

t = 45 s is the time taken
Solving,
