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Brut [27]
3 years ago
12

I appreciate the help on this physics question

Physics
1 answer:
Sidana [21]3 years ago
3 0
Not enough information
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Free electrons may be transferred between bodies by:
Tasya [4]
<span>Free electrons may be transferred between bodies by "Contact Action"

When positively charged body comes close to a negatively charged body, then electron flows from positively to negatively charged body

In short, Your Answer would be Option B

Hope this helps!</span>
8 0
3 years ago
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What is the most likely radiological device that a terrorist might use in a Weapons of Mass Destruction (WMD) incident?
zavuch27 [327]

Answer:Radiologic Dispersal Devices (RDD)

Explanation:

Radiologic Dispersal Device (RDD) is commonly known as dirty bomb. These devices require little more skill than is needed to make a conventional bomb and their components are easier to acquire. RDDs utilize conventional explosives to disperse a radioactive material packaged in the device, as opposed to a nuclear device, which creates radiation with its explosion.

7 0
3 years ago
A video game includes an asteroid that is programmed to move in a straight line across a 17-inch monitor according to the equati
Ainat [17]

Answer:

The asteroid's acceleration at this point is 2.71\ m/s^2

Explanation:

The equation that governs the trajectory of asteroid is given by :

x=6.5t-2.3t^3

The velocity of asteroid is given by :

v=\dfrac{dx}{dt}\\\\v=\dfrac{d(6.5t-2.3t^3)}{dt}\\\\v=6.5-6.9t^2

At some point during the trip across the screen, the asteroid is at rest. It means, v = 0

So,

6.5-6.9t^2=0\\\\t=0.971\ s                      

Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6.5-6.9t^2)}{dt}\\\\a=-13.8t                        

Put t = 0.971 s

a=-13.8\times 0.197\\\\a=-2.71\ m/s^2

So, the asteroid's acceleration at this point is 2.71\ m/s^2 and it is decelerating.

6 0
3 years ago
uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0
olganol [36]

Answer:

Fx1 (6 m) sin 60 = 300 (3 m) cos 60  balancing torques about floor

Fx1 = 900 * 1/2 / 5.20 = 86.6 N  this is the horizontal force that must be supplied by the wall to balance torques about the floor

This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

3 0
3 years ago
1.) A ball is thrown horizontally from the top of a building. What is the vertical velocity of the ball after 1 second?
BARSIC [14]
  1. 9.8
  2. zero
  3. 45
  4. not sure - 70
  5. Uniform accelerated motion
6 0
3 years ago
Read 2 more answers
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