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amid [387]
4 years ago
11

A more experienced colleague mentions to you that you should aim for a dissolved oxygen concentration around 1.0 mg/L at day 5 o

f the experiment. They show you data from a similar wastewater spill that happened last year, in which the BOD5 of the stream water was 60 mg/L. From your previous experiment, you found that the dissolved oxygen concentration at day 0 was 10 mg/L. Based on this information, what dilution factor, P, should you try in your reactor?
Chemistry
1 answer:
Sati [7]4 years ago
4 0

Answer:

3

Explanation:

Lt= Loe^(-kt)

Data:

Lo = 10 mg/mL

Assume k = 0.23/da

1. Calculate L5

L5 = 10e^(-5×0.23) = 10e^-1.15 = 10 × 0.317 = 3.17 mg/mL

2. Calculate the dilution factor

You expect to find L5 to be about 3

You want L5 to be about 1.

You should use a dilute your sample by a factor of 3.

P = 3

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At STP , how many molecules of nitrogen gas are in 2.24 L?
Oksanka [162]

Explanation:

At STP ,2.24 L contain 0.1 mole of N²

<h2>So,No. of molecules of N2 = 6.022*10²²</h2>
7 0
3 years ago
How many electrons does titanium have in the D orbital in its ground state electron configuration
LuckyWell [14K]

Titanium atoms have 22 electrons and the shell structure is 2.8. 10.2. The ground state electron configuration of ground state gaseous neutral titanium is [Ar].

6 0
3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
3 years ago
Could anyone help me with question 3?
Gwar [14]
Second one i think.......
3 0
3 years ago
The nation on average uses around 10 Million tons of salt per year to de-ice roads. How many kilograms of salt is this? (please
Westkost [7]
45359237 kilograms :))))))))))
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3 years ago
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