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amid [387]
3 years ago
11

A more experienced colleague mentions to you that you should aim for a dissolved oxygen concentration around 1.0 mg/L at day 5 o

f the experiment. They show you data from a similar wastewater spill that happened last year, in which the BOD5 of the stream water was 60 mg/L. From your previous experiment, you found that the dissolved oxygen concentration at day 0 was 10 mg/L. Based on this information, what dilution factor, P, should you try in your reactor?
Chemistry
1 answer:
Sati [7]3 years ago
4 0

Answer:

3

Explanation:

Lt= Loe^(-kt)

Data:

Lo = 10 mg/mL

Assume k = 0.23/da

1. Calculate L5

L5 = 10e^(-5×0.23) = 10e^-1.15 = 10 × 0.317 = 3.17 mg/mL

2. Calculate the dilution factor

You expect to find L5 to be about 3

You want L5 to be about 1.

You should use a dilute your sample by a factor of 3.

P = 3

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If 5.0 kJ of energy is added to a 15.5-g sample of water at 10.°C, the water is Group of answer choices
BaLLatris [955]

Answer:

The water is completely vaporized at this stage.

Explanation:

The complete question is

If 5.0 kJ of energy is added to a 15.5-g sample of water at 10.°C, the water is

-boiling

-completely vaporized

-frozen solid

-decomposed

-still a liquid

Energy added = 50 kJ = 50000 J

mass of water = 15.5 g = 0.0155 kg

temperature of water = 10 °C

We know that the energy posses by a mass of water at a given temperature is given as

H = mcT

where H is the energy possessed by the mass of water

m is the mass of the water

c is the specific heat capacity of water = 4200 J/ kg- °C

T is the temperature of the water

substituting values, the energy of this amount of water is

H = 0.0155 x 4200 x 10 = 651 J

If 50 kJ is added to the water, the energy increases to

50000 J + 651 J = 50651 J

Temperature of this water at this stage will be gotten from

H = mcT

we solve for the new temperature

50651 = 0.0155 x 4200 x T

50651 = 65.1 x T

T = 50651/65.1 = 778.05 °C

This temperature is well over 100 °C, which is the vaporization temperature of water, but less than 3000 °C for its molecules to decompose.

3 0
3 years ago
To name the compound written as cucl2 you would write\
MA_775_DIABLO [31]
Copper chloride ...............
5 0
3 years ago
An element with the valence electron configuration 4s24p4 would form a monatomic ion with a charge of fill in the blank 5 . In o
nordsb [41]

Answer:

Charge= -2.

Gains two electron into the 4p^4 to become 4p^6.

Explanation:

The element in the periodic table/chart that matches with the valence electron configuration is Selenium with full electron configuration of [Ar] 3d^10 4s^2 4P^4 which is a non-metal that is found in group 4 of the periodic table/chart.

Selenium can receive 2 more electrons on the 4p^4 to give a -2(minus 2) ion that is Se^2-.

Selenium can also loose 2 electron from 4s^2 to give a +2 ion that is Se^2+.

Selenium can also loose 2 electrons from 4s^2 and 2 electrons from 4p^4 to form Se^4+.

Selenium can also loose 2 electrons from 4s^2 and 4 electrons from 4p^4 to form Se^6+.

Thus, in order to form a monatomic ion with a charge(we will be making use of the most stable one). Thus, it will gain two more electron since this is easier to become 4s^2 4p^6.

4 0
3 years ago
What two general products do combustion reactions create? *
Dimas [21]
It would be carbon dioxide and water.

hope this helps you
7 0
3 years ago
How do you solve (1 x 1025) =3 x 10
Mrrafil [7]

Hey There!!~

Your best answer choice is 10280 or 10,280.

Because, 1 x 1025 = 1025 + 3 = 1028 x 10 = 10280 or 10,280.

Hope This Helps....!!

4 0
3 years ago
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