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AleksAgata [21]
3 years ago
14

How can I convert 2/5 in to a decimal

Mathematics
1 answer:
Inga [223]3 years ago
5 0

To convert all fractions to decimals there are two simple steps

1. Divide the numerator by the denominator

2. Round to the nearest tenth, hundredth, thousandth whatever. (If Necessary However)

But to get 2/5 to a decimal just divide 2 ÷5 by the 5.

Which equals 0.4

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Select the solutions of the equation. <br> 2x2-3x-5=0
meriva

Using the Quadratic formula

your answer would be A and C

5 0
3 years ago
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PLEAASE HELP
gladu [14]
Well you are given the equation so let's plug in for kaylib and see how many miles she can see
distance = sqrt [(3 * height) / 2]
d = sqrt [(3 *48) / 2]
d = sqrt (144 / 2)
d = sqrt (72)
d = sqrt (3 * 3 * 2 * 2 * 2)
d = 6 * sqrt (2)

You you did not list Addisons height but I will say she is at x feet above sea level. we plug in x for height:
d = sqrt [(3x) / 2]

It it says how much farther for Addison which means she can see farther. to find difference we just subtract kaylibs distance from Addison. so:
sqrt [(3x) / 2] - 6 * sqrt (2)

plug in your x and use a calculator to get a decimal approximation
8 0
3 years ago
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A guy wire runs from the top of a cell tower to a metal stake in the ground. Marques places a 11-foot tall pole to support the g
astra-53 [7]

The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.

<h3>How to solve the length?</h3>

Here, we have two similar right triangles, ΔABE and ΔCDE.

CD = 11 ft

DE = 2 ft

BD = 35 ft

First, find AB:

AB/11 = (35 + 2)/2

AB/11 = 37/2

Cross multiply

AB = (37 × 11)/2

AB = 203.5 ft

Then, apply Pythagorean Theorem to find AE:

AE = √(AB² + BE²)

AE = √(203.5² + 37²)

AE = 207 ft

Therefore, the length of the guy wire is 207 ft.

Learn more about Pythagorean theorem on:

brainly.com/question/654982

5 0
2 years ago
F(x, y, z) = yzexzi + exzj + xyexzk,c: r(t) = (t2 + 4)i + (t2 − 1)j + (t2 − 2t)k, 0 ≤ t ≤ 2(a) find a function f such that f = ∇
exis [7]
\nabla f(x,y,z)=\mathbf f(x,y,z)=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k

\dfrac{\partial f(x,y,z)}{\partial x}=yze^{xz}
\implies f(x,y,z)=\displaystyle\int yze^{xz}\,\mathrm dx=\dfrac{yz}ze^{xz}+g(y,z)
f(x,y,z)=ye^{xz}+g(y,z)

\dfrac{\partial f(x,y,z)}{\partial y}=e^{xz}=e^{xz}\dfrac{\partial g(y,z)}{\partial y}
\implies\dfrac{\partial g(y,z)}{\partial y}=0\implies g(y,z)=h(z)
f(x,y,z)=ye^{xz}+h(z)

\dfrac{\partial f(x,y,z)}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\partial h(z)}{\partial z}
\implies\dfrac{\partial h(z)}{\partial z}=0\implies h(z)=C
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8 0
3 years ago
I need help with this please
sergejj [24]

Answer:

<h2>5n</h2>

Step-by-step explanation:

5, 10 ,15, 20

it is going up in 5

so 5n

5 0
2 years ago
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