the orbit of the moon around earth causes the phases since the light from the moon is caused by a reflection of sunlight... btw wrong subject,....
I don't see an image. Sorry I couldn't help you
The wave characteristic that is the same for both waves is wavelength.
- Two waves with the same frequency will also have the same wavelength, amplitude, speed, and period. When two waves are travelling at the same frequency, it denotes that their duration and amplitude are also the same.
- When two waves of the same frequency and amplitude interfere constructively, their peaks and troughs align as shown in diagram A above. As a result, the original waves' amplitude is doubled, resulting in a sound wave that is twice as loud.
Thus, Equal frequencies are shared by two waves moving through the same region in the same direction.
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Explanation:
It would be easier to lift the hammer, during the nailing, in Pluto than on earth but it would require more hammer jacks to drive the nail through the floorboard. This is because the gravity on Pluto is weaker than on Earth. The additional acceleration of the hammer (due to gravity) would be lesser hence you would require to put in a bit more energy for the downforce of the hammer.
On the sun, it would be difficult to lift the hammer than here on earth. This is because the gravity of the sun is much greater than on earth. If you would manage to lift the hammer, the downforce of the hammer on the nail would have an added acceleration of the gravity of the sun hence the force of the hammer hitting the nail would be higher hence rapidly driving it through the floorboard.
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Answer:
v_f = 6.92 x 10^(4) m/s
Explanation:
From conservation of energy,
E = (1/2)mv² - GmM/r
Where M is mass of sun
Thus,
E_i = E_f will give;
(1/2)mv_i² - GmM/(r_i) = (1/2)mv_f² - GmM/(r_f)
m will cancel out to give ;
(1/2)v_i² - GM/(r_i) = (1/2)v_f² - GM/(r_f)
Let's make v_f the subject;
v_f = √[(v_i)² + 2MG((1/r_f) - (1/r_i))]
G is Gravitational constant and has a value of 6.67 x 10^(-11) N.m²/kg²
Mass of sun is 1.9891 x 10^(30) kg
v_i = 2.1×10⁴ m/s
r_i = 2.5 × 10^(11) m
r_f = 4.9 × 10^(10) m
Plugging in all these values, we have;
v_f = √[(2.1×10⁴)² + 2(1.9891 x 10^(31)) (6.67 x 10^(-11))((1/(4.9 × 10^(10))) - (1/(2.5 × 10^(11)))] 20.408 e12
v_f = √[(441000000) + 2(1.9891 x 10^(30)) (6.67 x 10^(-11))((16.408 x 10^(-12))]
v_f = √[(441000000) + (435.38 x 10^(7))
v_f = 6.92 x 10^(4) m/s