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grigory [225]
3 years ago
15

What is the single most important factor that determines why Earth (or almost any planet in the Solar System) experiences season

s?
Physics
1 answer:
kirill [66]3 years ago
6 0

Answer:

Planetary seasons are caused by two factors:

1. axial tilt and

2. variable distance from the sun

Explanation:

Earth's orbit is nearly circular and so has little effect on climate. It's our planet's axial tilt that causes almost all seasonal changes.

You can read further; Planetary seasons

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PLEASE HELP! I GIVE LOTS OF POINTS!
zepelin [54]

Answer:

this hurts my brain. bro i'm going into physics next year and im over here think physics is easy well you just proved me wrong

Explanation:

4 0
4 years ago
Read 2 more answers
How long will it take to melt 3500 kg of steel in a 50 kW oven operating at 65% efficiency from room temperature to 1600°C?
zepelin [54]

Answer:

71195 seconds or 19.8 hours

Explanation:

Because the steel will be melted, beginning from room temperature, energy is needed to heat it from room temperature to 1600°C and another to melt it at 1600°C.

We take room temperature to be 27°C, the specific heat capacity of steel to be 420 J/kg/K and the specific latent heat of fusion of steel to be 440 J/kg.

The heat required to heat the steel from room temperature to 1600°C is given by

H_S = mc_S\delta\theta

m is the mass, c_S is the specific heat capacity and \delta\theta is the change in temperature.

H_S = 3500\times420\times(1600-27) = 2312310000

The heat required to melt it at 1600°C is

H_L = ml_S

m is the mass and l_S is the specific latent heat of fusion of steel.

H_L = 3500\times440 = 1540000

Adding both, the heat required is 2312310000+1540000=2313850000\text{ J}

Because the oven is 65% efficient, its output power = 65\%\times50000 = 32500 \text{ W}

Now, energy = power * time

Time = Energy/power

t = \dfrac{2313850000}{32500}=71195 \text{ seconds} = 19.8 \text{ seconds}

4 0
3 years ago
If it requires 7.0 J of work to stretch a particular spring by 1.8 cm from its equilibrium length, how much more work will be re
belka [17]

Answer:

56 J

Explanation:

The following data were obtained from the question:

Energy 1 (E₁) = 7 J

Extention 1 (e₁) = 1.8 cm

Extention 2 (e₂) = 1.8 + 3.6 = 5.4 cm

Energy 2 (E₂) =?

Energy stored in a spring is given by the following equation:

E = ke²

Where E is the energy.

K is the spring constant.

e is the extension.

E = ke²

Divide both side by e²

K = E/e²

Thus,

E₁/e₁² = E₂/e₂²

7/ 1.8² = E₂/ 5.4²

7 / 3.24 = E₂/ 29.16

Cross multiply

3.24 × E₂ = 7 × 29.16

3.24 × E₂ = 204.12

Divide both side by 3.24

E₂ = 204.12 / 3.24

E₂ = 63 J

Thus, the additional energy required can be obtained as follow:

Energy 1 (E₁) = 7 J

Energy 2 (E₂) = 63 J

Additional energy = 63 – 7

Additional energy = 56 J

8 0
3 years ago
The astrometric technique of planet detection works best for
denpristay [2]

The astrometric technique of planet detection works best for massive planets around nearby stars.

6 0
3 years ago
A motor does 3,441 joules of work in 13.66 seconds. What is the power of the motor?
il63 [147K]

Answer:

Power = 251.9 Watts

Explanation:

Power = Work Done / Time taken

Power = 3441 / 13.66

Power = 251.9 Joule / Second

Power = 251.9 Watts

5 0
3 years ago
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